Which of the following are the appropriate hypotheses to be tested? Ho=0.69 Ha> 0.69 0 Ho: p = 0.69 Ha: p > 0.69 Ho: P = 0.69 Ha: p > 0.69 Ho: μ = 0.69 Ha: μ> 0.69 Ho: X = 0.67 H₂: x > 0.67 What is the appropriate z-test statistic value for this test? 0.72 0.1214 0.69 0.02569 1.16777 The resulting p-value is 0.1214, hence we do not have enough evidence against the null hypothesis and in support of the alternative hypothesis. Provide a sentence or two that explains, using the context of the problem, the p-value as a shaded region under a normal curve (this is referred to as the interpretation of the p-value)

The Bureau of Labor Statistics reports that the official unemployment rate for Black people was 10.4% and 4.7% for White people in February 2015. Select all correct answers for this question. O The samples of white and black people are independent. The explanatory variable is the unemployment rate. The response variable is the unemployment rate. The response variable is race.

By a small margin, Facebook remains the top choice of social media over all ages, with 29% using Facebook most often among those using social media sites. However, more visually oriented social networks such as Snapchat and Instagram continue to draw in younger audiences. When asked "Which one social networking brand do you use most often?" the results in the table show the top brands chosen by Americans aged 12-34 who currently use any social networking site or service. Social M edia Site Faceboo k Snapchat Instagra m Twitter Percentage That Use Most Often 29 28 26 6 20 (a) What is the sum of the percentages for these top social media sites? Give your answer as an exact number. Macmillan Learning top social media sites: What percent of Americans aged 12-34 use other social media sites most often? Give your answer as an exact number. other social media sites: do %

You conducted a study to assess the effect of smoking on systolic blood pressure. The results showed that there was a significant association between the two variables, with an odds ratio of 1.5. Explain this finding to someone who has no background in epidemiologic research.