When stained with Giemsa (G-Banding staining), the centromere will be stained: Question 28 options: more robustly (dark band) less robustly (light band)

Based on the attached image, if we are using the Holliday junction model of recombination, where exactly would be the positions where DNA is cut? Would it be to the right because of branch migration?

a- What is De Bruijn graph, and why it is used? b- Given the folowing string ACGCGTCG. draw De Bruijn graph where K-3

Explain The noncrossover pathway?

Question: Genes A, B, C, and D are on the same chromosome. Consider the data and draw a genetic map:     Relationship RF B - D 14% C - D 12% A - D 6% B - C 2% A - B 8%

A pair of paralogous repeats, A and B, have 96% sequence similarity and therefore can promote non-allelic homologous recombination (NAHR). They exist in four possible arrangements in a genome, illustrated below as arrangements 1 – 4. What is the result of NAHR between repeats A and B in arrangement 1? A.Translocation between chromosomes 1 and 2 resulting in monocentric chromosomes B.Deletion or duplication of the region between A and B C.Translocation between chromosomes 1 and 2 resulting in acentric and dicentric chromosomes D.Inversion of the region between A and B

Cierra Ballierajh - Pedigree - Go × + resentation/d/1vcm90PtSWx93LtacvlAUJk84UPuJ9DpU8nS94-XrBPQ/edit#slide-id.g97df83752a_0_315 Fit Co add speaker notes 4× ☆ C Quick... 20 + BIUA - PEDIGREES: Problem 7 (continued) This pedigree shows the inheritance of a type of X-linked color blindness. It is a recessive trait. Carriers have NOT been half-shaded in this pedigree. I 어디어디 2 3 4 II 1 2 3 QUESTIONS ... 3. Use the letter "b" to represent the color blindness allele. What is the genotype of individual IV-I? bb 4. What evidence is there that this type of color blindness is recessive? III IV C 3 Emmatheteachie 2020 65°F Prt Scn Home End