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When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s1. Calculate Km for the substrate SAD.

When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s1. Calculate Km for the substrate SAD.

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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could you elaborate more on the process of step 2? it isn't explained vey well

Get live help whenever you need from online tutors! Try bartleby tutor today > Q SEARCH & ASK AN EXPERT A CHAT Vx MATH SOLVER An enzyme is discovered that catalyzes the chemical reaction A team of motivated researchers sets out to study the enzyme, which they call happyase. They find that the kcat for happyase is 600 s and carry out several additional experiments. When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s. Calculate Km for the substrate - SAD. SAD = HAPPY Transcribed Image Text: SAD = HAPPY Expert Solution Step 1 Enzymes are the biomolecules which acts as catalysts for many biochemical reactions and increases the rate of reaction by decreasing the activation energy required for the reaction. Step 2 In the given question, the given enzymatic reaction that is catalyzed by enzyme Happyase is: SAD = HAPPY The given concentration of substrate [SAD] is 40 uM, and enzyme concentration is 20 nM. The Kcat for the enzyme is 600 /sec. The rate of reaction (Vo) is 9.6 uM/sec. The Km can be calculated as follows: Vтахутах TE; ] Vmax[S Km + [S Кcat 3D — Кcat x| E, Vтах — 600 x 20 х 10-3 риM/secVmax 12 иМ/secVo Step 3 Hence, the Km for the substrate SAD is 10 µM.
Transcribed Image Text:Get live help whenever you need from online tutors! Try bartleby tutor today > Q SEARCH & ASK AN EXPERT A CHAT Vx MATH SOLVER An enzyme is discovered that catalyzes the chemical reaction A team of motivated researchers sets out to study the enzyme, which they call happyase. They find that the kcat for happyase is 600 s and carry out several additional experiments. When [Et] = 20 nM and [SAD] = 40 µM, the reaction velocity, V0, is 9.6µM s. Calculate Km for the substrate - SAD. SAD = HAPPY Transcribed Image Text: SAD = HAPPY Expert Solution Step 1 Enzymes are the biomolecules which acts as catalysts for many biochemical reactions and increases the rate of reaction by decreasing the activation energy required for the reaction. Step 2 In the given question, the given enzymatic reaction that is catalyzed by enzyme Happyase is: SAD = HAPPY The given concentration of substrate [SAD] is 40 uM, and enzyme concentration is 20 nM. The Kcat for the enzyme is 600 /sec. The rate of reaction (Vo) is 9.6 uM/sec. The Km can be calculated as follows: Vтахутах TE; ] Vmax[S Km + [S Кcat 3D — Кcat x| E, Vтах — 600 x 20 х 10-3 риM/secVmax 12 иМ/secVo Step 3 Hence, the Km for the substrate SAD is 10 µM.
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