When 12.27 grams of ice at - 20°C have absorbed 2500 calories of heat, what is the temperature of the resulting water? specific heat of ice = 0.50 cal/g °c specific heat of water = 1.0 cal/g °C latent heat of fusion = 80 cal /g

A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg.°C Initial temperature of aluminum Mass of aluminum Final temperature of mixture (a) Use these data to determine the specific heat of aluminum. J/kg. °C (b) Is your result within 15% of 900 J/kg . °C? Yes No Need Help? 26.8°C 0.199 kg 66.4°C Read It

A 0.290 kg aluminum bowl holding 0.815 kg of soup at 25.0°C is placed in a freezer. What is the final temperature (in °C) if 391 kJ of energy is transferred from the bowl and soup, assuming the soup's thermal properties are the same as that of water?     °C

A person tries to cool down her bath water by adding 5.0 Kg of ice at 0°C to 75.0 Kg of water at 70°C. What is the final temperature of the water? (Lf = 333 KJ/Kg & cH2O =4186 J/Kg°C)

What is the ratio of the energy required to warm 125 g of Ice (0.0 \deg C) to body temperature (37 \deg C) to warming the same amount of water through the same temperature change? Answer format is the number Eice/Ewater = (2 significant figures) Latent Heat of Fusion of Water: 335, 000 J/kg Specific Heat Capacity of Water: 4186 J/kg/\deg C

A bar of pure gold is heated to 105.0 °C. The specific heat capacity of gold is 1.29x10² J/1kg~°C). The gold is placed into 600.0 mL of ethyl alcohol initially at a temperature of 35.0 °C. The final temperature of the mixture is 37.0 °C. What is the mass of the gold?

A chunk of metal with a mass of 85.0 grams and a specific heat of 759 joules per kilogram·kelvin is heated to 78.9 degrees Celsius and placed in 122 milliliters of water (c = 4186 J/kg·K) at 18.6 degrees Celsius. What is the final temperature of the metal and water? Hint: The heat lost by the metal is gained by the water, so the sum of the heats is zero.

A student measures the following data in a calorimetry experiment designed to determine the specific heat of aluminum. (Do not assume atmospheric pressure.) Initial temperature of water and calorimeter:         70°C Mass of water: 0.400 kg Mass of calorimeter: 0.040 kg Specific heat of calorimeter: 0.63 kJ/kg · °C Initial temperature of aluminum: 26.6°C Mass of aluminum: 0.200 kg Final temperature of mixture: 65.8°C Use these data to determine the specific heat of aluminum.

A 20-g ice cube floats in 150 g of water in a 100-g copper cup; all are at a temperature of 0°C. A piece of lead at 86°C is dropped into the cup, and the final equilibrium temperature is 12°C. What is the mass of the lead? (The heat of fusion and specific heat of water are 3.33 x 105 J/kg and 4,186 J/kg °C, respectively. The specific heat of lead and copper are 128 and 387 J/kg °C, respectively.) kg Need Help? Read It Master It

Measurement of specific heat of metals Aluminum Cupper Mass of inner cup of calorimeter mcal, g 50 50 Specific heat of calorimeter Ccal, cal/(g °C) Specific heat of water Cw, cal/(g °C) 0.217 0.217 1.00 1.00 Mass of metal Mm, g 80 140 Mass of inner cup + water mcal + Mw, g 220 240 Mass of water Mw, g 170 190 Initial temperature of calorimeter and water to, °C Initial temperature of metal tm, °C 22 22 100 100 Final equilibrium temperature tr, °C 30 26 Thermal energy gain by calorimeter and water Qgain, cal Specific heat of metal Cm, cal/(g °C) Standard specific heat of metal Cst , cal/(g °C) 0.217 0.093 |% error Thermal energy lost = Thermal energy gained Thermal energy Q = cmAt %3D %3D Specific heat C |Thermal energy lost by metal = Thermal energy gained by (water + calorimeter) %3D EmMm(tm-tf)=(ccatMeat +CwMw)(tp- to) %3D (Ccaimcal+ Cymw)(tf- to). Gm = %3D Mm(tm - t;) |