Measurement of specific heat of metals Aluminum Cupper Mass of inner cup of calorimeter mcal, g 50 50 Specific heat of calorimeter Ccal, cal/(g °C) Specific heat of water Cw, cal/(g °C) 0.217 0.217 1.00 1.00 Mass of metal Mm, g 80 140 Mass of inner cup + water Mcal + Mw, g 220 240 Mass of water Mw, g 170 190 Initial temperature of calorimeter and water to, °C Initial temperature of metal tm, °C 22 22 100 100 Final equilibrium temperature tr, °C 30 26 Thermal energy gain by calorimeter and water Qgain, cal Specific heat of metal Cm, cal/(g °C) Standard specific heat of metal Cst , cal/(g °C) 0.217 0.093 % error Thermal energy lost = Thermal energy gained Thermal energy Q = cmAt Specific heat c Thermal energy lost by metal = Thermal energy gained by (water + calorimeter) GmMm(tm-tf)= (ceatMeat+CwMw)(t,-to) | (Ccaimcal+ Cwmw)(tp- to) mm(tm-t;) Gm =

The temperature of a 5.00-kg lead brick is increased by 525 C°. If the specific heat capacity of lead is 128 J/(kg.C°), what is the increase in the mass of the lead brick when it has reached its final temperature? O 5.80 × 10- -11 kg O 9.12 × 10-11 kg O 1.60 × 10-12 kg O 3.73 × 10-12 kg O 2.80 × 10-12 kg

A student obtains the following data in a calorimetry experiment designed to measure the specific heat of aluminum. Initial temperature of water and calorimeter 70.3°C Mass of water 0.402 kg Mass of calorimeter 0.04 kg Specific heat of calorimeter 0.60 kJ/kg.°C Initial temperature of aluminum Mass of aluminum Final temperature of mixture (a) Use these data to determine the specific heat of aluminum. J/kg. °C (b) Is your result within 15% of 900 J/kg . °C? Yes No Need Help? 26.8°C 0.199 kg 66.4°C Read It

A machinist wishes to insert a copper rod with a diameter of 8 mm into a hole with a diameter of 7.996 mm. By how much would the machinist have to lower the temperature (in °C) of the rod to make it fit the hole?  °C