What would be the genotypes of the female F1 flies? ____​phenotype? ______   What would be the genotypes of the male F1 flies? ___​phenotype? _______       Do a Punnett square for the F2 results if one of the F1 females mated with one of the F1 males.

Biology: The Unity and Diversity of Life (MindTap Course List)
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Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
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Chapter10: Control Of Gene Expression
Section: Chapter Questions
Problem 3CT: Almost all calico cats (one is pictured in FIGURE 10.7B) are female. Why? B When this calico cat was...
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ACTIVITY 5: Sex-linked inheritance

 

In many animals, the sex of an individual is determined by which sex chromosomes (X or Y) are inherited.  In mammals (and the fruit fly Drosophila), females have 2 X chromosomes and males have one X and one Y.  The X and Y are an unusual pair of homologous chromosomes.  The X is large and contains thousands of genes, while the Y is small and contains few genes.  Most genes on the X are not found on the Y, so males possess only one copy of each X-linked gene and females have 2 copies.  This means that X-linked recessive traits are expressed more often in males.

 

Eye color is a sex-linked trait in Drosophila.  The allele for red eyes is dominant to the allele for white eyes.  Because this gene is on the X chromosome, the alleles are written as XR and Xr.  

 

A. Do a Punnett square for a cross between a homozygous red-eyed female (XR XR ) and a white-eyed male (Xr Y).  

 

 

 

 

 

 

 

 

What would be the genotypes of the female F1 flies? ____​phenotype? ______

 

What would be the genotypes of the male F1 flies? ___​phenotype? _______

 

 

 

Do a Punnett square for the F2 results if one of the F1 females mated with one of the F1 males.

 

 

 

 

 

 

 

 

*To show results of sex-linked traits:

1. Divide phenotypes into males and females first, keep results as fractions (or %).

2. List the phenotypes, with the corresponding genotype (in parentheses) next to each phenotype.

 

Males:

 

 

Females:

 

 

 

 

B. A sex-linked trait in humans: hemophilia = blood clotting disorder.

 

Normal clotting (XN) is dominant to hemophilia (Xn).

Do a Punnett square for a normal clotting (homozygous dominant) woman and a man with hemophilia.

 

 

 

 

 

 

 

 

 

 

*To show results of sex-linked traits:

1. Divide phenotypes into males and females first, keep results as fractions (or %).

2. List the phenotypes, with the corresponding genotype (in parentheses) next to each phenotype.

 

Males:

 

 

Females

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