what is the property of the solution that makes log(concentration) Vs electrochemical potential deviates from linear line at high concentrations?
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what is the property of the solution that makes log(concentration) Vs
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- V=62 log 10 (C0/Ci ) for a positive ion at 37 degrees Celsius. What is theoretical ratio of solution ion across the membrane when the resting membrane potential is 124 mV?You have a semi permeable membrane with a membrane potential of -90mV. You also have two ions that are both permeable to the membrane, Na and Cl. Na has a concentration of 10mM inside the membrane and 120mM outside the membrane. Cl has a concentration of 1.5mM inside the membrane and 77.5mM outside the membrane. Use the nernst equation to calculate the electrochemical equilibrium of both ions, and show in which direction the netflux would be for each ion.The simple form of |Hoff equation is: II = [B]RT In this equation the [B] is the molar concentration of solute. So: n m [B] = v MV = cg /MA Where c, the mass concentration of the solute is in the total volume of solution and M, is the molar mass of the solute. This equation can be replaced in the previous one to get: RT II = MA In this equation molar mass of given solute can be detemined from the slope of the II vs Cz plot. This equation applies only to solutions that are sufficiently dilute to behave as ideal-dilute solutions. In the case of non-ideal solutions, however, the extended formula is: II = [B]RT{1+ k. [B] + n. [B]² + ...} Biological macromolecules dissolve to produce solutions that are far from ideal, but we can still calculate the osmotic pressure by assuming that the van't Hoff equation is only the first term of a lengthier expression: II [B]RT(1+ b. [B]) II = RT + bRT. [B] [B] II = RT + bRT./M. */Ma п RT ÞRT Ca MA MA In this equation molar mass of given biomolecule can…
- When 2.43 g of a nonelectrolyte solute is dissolved in water to make 435 mL of solution at 25 °C, the solution exerts an osmotic pressure of 895 torr. What is the molar concentration of the solution? concentration: 0.045 M Incorrect How many moles of solute are in the solution? moles of solute: 0.034 mol Incorrect What is the molar mass of the solute? molar mass: 69.12 g/mol IncorrectIn the Nernst equation [V = 62 log10 (Co/ Ci)], the term Co represents: the intracellular concentration of calcium the extracellular concentration of potassium the extracellular concentration of sodium the intracellular concentration of potassium the membrane potential (in millivolts)Name the two component that contribute to the electrochemical gradient (hint is in the name!) and briefly describe what they are.
- what is an electro gradientConsider a suspension of particles (isoelectric point is at pH 6) in water at pH 2 and a NaCl concentration of 0.001 M. Describe how the strength of repulsion varies with the following changes, assuming all other conditions remain constant. Give a description (more than just increase or decrease) in terms of the effect on the double layer thickness and the zeta potential. (a) Change from 0.001 M NaCl to 0.1 M NaCl, (b) Change from pH = 2 to pH = 5.Calculate the effective quantity (g) of sodium chloride related to tonicity in 100 mL of an intravenous fluid labeled "5% dextrose in 0.45% sodium chloride," and indicate whether the solution is isotonic, hypotonic, or hypertonic.
- In the Nernst equation [V = 62 log10 (Co/ Ci)], the term Co represents: the intracellular concentration of potassium the intracellular concentration of chloride the membrane potential (in millivolts) the extracellular concentration of sodium the extracellular concentration of potassiumIs there a way to predict how much electrical force is required to exactly balance the tendency of an ion to diffuse down its concentration gradient?Calculate the effective quantity (g) of sodium chloride related to tonicity in 100ml of an intravenous fluid labeled "5% dextrose in 0.45% sodium chloride," and indicate whether the solution is isotonic, hypotonic or hypertonic. The answer is Hypertonic and 1.35g NaCl but I don't understand how to get the answer.