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Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Question
given the maximal number of the binary sequence max seq (e.g., max seq=7 for
three bits), what are the expression (in term of max seq) of the maximal sizes of
sending window for go-back-n and selected-repeat protocols? you need to demonstrate
the counter-examples on why window sizes larger than the maximum can fail. repeat
the same question for the receiving window sizes
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- To address the scenario where the sequence number space is k bits, it is recommended to explore the selective-repeat and Go-Back-N strategies as potential solutions. What is the maximum size of the sender window?arrow_forwardConsider using both the Go-Back-N and selective-repeat strategies if the sequence number space has k bits. What is the maximum allowable sender window size?arrow_forwardplease please answer asaparrow_forward
- You can use both the selective-repeat and Go-Back-N approaches to solve the problem if the sequence number space is k bits in size. How large of a window can we construct for the sender?arrow_forwardIn the congestion control method of TCP we are having a connection between nodes A and node B which is called connection X. There is another TCP connection between node C and node D which is called connection Y. The initial threshold window size for connection X is 20 KB and for Y is 16 KB. Both the connections X, Y are working independently and follow the Additive increase multiplicative decrease algorithm (AIMD) for congestion control with a maximum segment size of 2 KB. The first timeout occurs at the fifth transmission in connection X and at the sixth transmission in connection Y. After every third transmission from timeout, you again encounter the timeout in both X and Y. At which transmission the connection Y reaches to the same threshold value of the connection X for the first time.arrow_forwardI need the answer as soon as possiblearrow_forward
- Problem with constructing MAC. The messages X to be authenticated consists of z independent blocks, so that: X = x1||x2|| . . . ||xz, where every xi consists of |xi| = 8 bits. The input blocks are consecutively put into the compression function ci = h(ci−1, xi) = ci−1⊕xi At the end, the MAC value: MACk(X) = cz+k mod 28 is calculated, where k is a 64-bit long shared key. Describe how exactly the (effective part of the) key k can be calculated with only one known message X.arrow_forward4. In this problem, you will derive the efficiency of a CSMA/CD-like multiple access protocol. In this protocol, time is slotted and all adapters are synchronized to the slots. Unlike slotted ALOHA, however, the length of a slot (in seconds) is much less than a frame time (the time to transmit a frame). Let S be the length of a slot. Suppose all frames are ofarrow_forward
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