Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Consider applying the Go-Back-N and selective-repeat techniques if the sequence number space is k-bit long. When sending data, what is the maximum size of the sender window that may be used?
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- Suppose that you pick a bit string from the set of all bit strings of length ten. What is the probability that the bit string has more 0s than 1s?arrow_forwardIn the hamming code C (7, 4), three redundant bits are generated as follows:0 2 1 0 r = a ⊕ a ⊕ a1 3 2 1 r = a ⊕ a ⊕ a2 3 1 0 r = a ⊕ a ⊕ aarrow_forward1. Generate the Hamming-code for the following 12-bit data string : 1 0 1 0 1 1 0 1 1 1 0 1 Show that the generated binary string does not have any errors.arrow_forward
- If the sequence number space contains k bits, think about using both the Go-Back-N and selective-repeat techniques. What is the largest sender window that is permitted?arrow_forwardHow many bits are needed to digitally record 90 seconds of your favorite music tune? The sampling rate commonly used for music is 44.1 kHz (i.e. 44100 Hz). Each sample is represented using 16 bits. Note that music is usually recorded in stereo, requiring hence twice the number of samples that would be needed for a non-stereo recording of an audio signalarrow_forwardDraw a FSA which accepts all binary strings which start with 0, the length of the string is even but the number of 1's in the string is odd. 0111, 01 and 000111 should be accepted while 111 and 0011 should notarrow_forward
- 3. The ALU supported set on less than (slt) using just the sign bit of the adder. Lets try a set on less than operation using the values -710 and 610. To make it simpler to follow the example, lets limit the binary representations to 1 bits: 10012 and 01102. Then we get 10012 – 01102 = 10012+10102 = 00112. This result would suggest that –7 > 6, which is clearly wrong. Hence, we must factor in overflow in the decision. Ainvert Operation Binvert Carryln Result b. 2 Less 3 Set Overflow Overflow detection There are 4 possible cases for the Set and Overflow detection bits generated by the ALU, shown in the truth table below. Fill in the desired value for slt for each of these cases, and then explain how use a logical operation to combine the Set and Overflow detection bits to get this desired outcome. Draw the changes you need to make to the ALU to get the correct slt behavior on the diagram above. Set Overflow SLT 1 1 1 1arrow_forwardConsider all bit (binary digit) strings of length 12. How many begin with 110? How many begin with 11 and end with 10? How many begin with 11 or end with 10? How many have exactly four 1s?arrow_forwardIf the sequence number space includes k bits, you should think about employing the Go-Back-N strategy as well as the selective-repeat strategy. What is the largest size sender window that is permitted to be?arrow_forward
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