Weight loss: In a study to determine whether counseling could help people lose weight, a sample of people experienced a group-based behavioral intervention, which involved weekly meetings with a trained interventionist for a period of six months. The following data are the numbers of pounds lost for 14 people. Assume the population is approximately normal. Perform a hypothesis test to determine whether the mean weight loss is greater than 13 pounds. Use the a = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. 21.2 27.5 6.5 22.8 20 11.5 16.2 19.7 36.3 32.5 11.1 34.8 22.4 17.9 Send data to Excel Part: 0 / 5 Part 1 of 5 (a) State the appropriate null and alternate hypotheses. Ho: H₁: OO 0=0 0*0 μ

UBS Wealth Management UK periodically ask their customers to evaluate their financial consultants and services. The higher the customer rating, the better the perceived service. The maximum rating is 7. Independent samples of two financial consultants are given below. Consultant A has 10 years' experience, Consultant B has 1 years' experience. Use α = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating.   Consultant A Consultant B N1 = 16 N2 = 10 Mean1 = 6.82 Mean2 = 6.25 S1= 0.64 S2 = 0.75 State the null and alternative hypothesis, Compute the value of the test statistic. What is the p-value? What is your conclusion?

How much customers buy is a direct result of how much time they spend in the store. A study of average shopping times in a large national houseware store gave the following information (Source: Why We Buy: The Science of Shopping by P. Underhill). Women with female companion: 8.3 min.Women with male companion: 4.5 min. Suppose you want to set up a statistical test to challenge the claim that a woman with a female friend spends an average of 8.3 minutes shopping in such a store. (a) What would you use for the null and alternate hypotheses if you believe the average shopping time is less than 8.3 minutes? Ho: ? = 8.3; H1: ? ≠ 8.3Ho: ? < 8.3; H1: ? = 8.3    Ho: ? = 8.3; H1: ? < 8.3Ho: ? = 8.3; H1: ? > 8.3 Is this a right-tailed, left-tailed, or two-tailed test? right-tailedtwo-tailed    left-tailed (b) What would you use for the null and alternate hypotheses if you believe the average shopping time is different from 8.3 minutes? Ho: ? = 8.3; H1: ? > 8.3Ho: ? ≠ 8.3; H1: ? = 8.3…

According to a report on consumer fraud and identity theft, 22% of all complaints for a year were for identity theft. In that year, Wisconsin had 787 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Wisconsin had a higher proportion of identity theft than 22%? Test at the 1% level. State the hypotheses. Ho: p? v Ha: p|? v Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. Z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .01, reject Họ. O Since the p-value is greater than .01, reject Ho. O Since the p-value is less than .01, fail to reject Ho. O Since the p-value is greater than .01, fail to reject Ho. Interpret the results. O At the 1% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Wisconsin is not equal to…