5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
5. The following function indexCounter aims to find and return all the indices of the
element x in a list L. if x is not in the list L, return an empty list. However, the
implementation has a flaw, so that many times it will return error message. Can you fix the
flaw?
def indexCounter(L, x):
indexList
[]
startIndex = 0
while startIndex < len(L):
indexList.append (L.index (x, startIndex))
startIndex = L.index (x, startIndex) + 1
return indexList
Transcribed Image Text:5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList
Expert Solution
Program –

def indexCounter(L, x):

    indexList = []

    startIndex = 0

   

    while startIndex < len(L):

        try:

            indexList.append(L.index(x, startIndex))

            startIndex = L.index(x, startIndex) + 1

        except ValueError as e:

            break

    return indexList

   

L = [1, 2, 3, 4, 5, 1, 6]

print (indexCounter(L, 1))

Output –

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