Water is drained from a large reservoir using two horizontal plastic pipes connected in series. The first pipe is 20 m long and has a 10-cm diameter while the second pipe is 35 m long and has a 4-cm diameter. The water level in the reservoir is 18 m above the centerline of the pipe. Given: Fitting Pipe entrance Pipe exit K values 0.5 0.46 Density of water is 1000 kg/m³, Dynamic viscosity (μ) of the water is 1.14x10-3 Pa·s, Surface roughness of the plastic pipe (ε) = 0 (smooth pipe) Determine a) the flow velocity of water in both pipes; and b) the discharge rate of water from the reservoir. 18 m Water tank 35 m 20 m

Q2- Water density =1000 kg/m and viscosity is 0.001 Ns/m², is pumped between two reservoirs at 0.2m/s through a 400 m of 8 cm diameter Cast Iron pipe and several minor losses as shown in the figure. Compute the pump power required in kW. Use the last one digit of your ID number for Z1 level in meter. Screwed Z2= 50 m regular 90° elbow Sharp exit Z;= ID m Sharp entrance Half-open gate valve `bend radius Pump Open globe valve 8 cm diameter

A venturi meter with a 12 cm throat is installed in a 18 cm pipe which is inclined upward at an angle of 30° to the horizontal. If the distance between pressure tape along with the pipe is 2 meters, the differential pressure is 90 kPa. What is the discharge of water in m3/s? Assume coefficient is 0.98

A pump delivers water from a tank (A)X water surface elevation-110m) to tank B (water surface elevation= 170m). The suction pipe is 45m long and 35cm in diameter the delivered pipe is 950m long 25cm in diameter. Loss head due to friction hf1 = 5m and h2 3m If the piping are from pipe(1)= steel sheet metal pipe(2)= stainless – steel Calculate the following i) ii) The discharge in the pipeline The power delivered by the pump.

The option thats true

Imagine that you are recently bought a 2-floor house and want to improve the water installation at the top floor which is 15 m from the water meter. Suppose that the water installation is poor due to 3 reasons: The city water pressure is not adequate (p = 200 kPa), the piping has a small diameter (D = 1.27 cm) and has been crudded up, increasing its roughness (e/D = 0.05). After a brief analysis you decide that there are 2 options to solve the problem: Either replacing the piping system with the smooth new pipe (D = 1.9 cm) or installing the boost pump (p = 300 kPa) while keeping the old piping system. By neglecting minor losses, which one would be more effective? (keeping in mind that combining these 2 options will surely solve the problem, but with more expenses)

As shown in the figure below, a cylindrical tank with a hole in the bottom and an air vent in the top is being filled with water. Given the following: Dtank = 4 ft hill = 8 ft NOG height of water in tank when tank is filled Qin = 10 gal/min %3D NOT UPL TO CHE diameter of hole Find: volumetric flowrate into tank EGG EXAM into the tank in slugs/second OT UPS XAM O NOT U EXAM (c) The rate at which the water level in the tank is mass flowrate (in slugs/second) of the water (b) The mass flowrate (in slugs/second) out of the tank UPLOAD TO CHE NOT UPLOAD when the water level reaches the fill height DO NOT UPL rising (in inches/minute) when the water level NOT UPL PLOAD TO CHEGG NOT UPLOAD TO CHEGG EXAM TO CHEGG EXAM OD TO CHEGG UP reaches the filled height то снE LOAD vent Dtank DO DO DO NOT UPLOADTO EXAM EX DO 0 DONOT UPLOA T Dhole G EXAM TO CNGO UPLOA hole mdotout

For the piping system of Fig. , all pipes are concretewith a roughness of 0.04 in. Neglecting minor losses, computethe overall pressure drop p1 - p2 in lbf/in2 ifQ =20 ft3/s. The fluid is water at 20°C.

The water is flowing through a pipe having diameters 30 cm and 21 cm at sections land 2 respectively. The rate of flow through pipe is 40 litres/s. The section 1 is 7 m above datum and section 2 is 3 m above datum. If the pressure at section 1 is 37 N/cm? , find the following by neglecting losses: (ENTER ONLY THE VALUES BY REFERRING THE UNIT GIVEN IN BRACKETS) ) Area of cross section of section1 (unit in m?) = Area of cross section of section2 (unit in m?) = velocity at section 1 (unit in m/s) = velocity at section 2 (unit in m/s) = (ii) difference in datum head (Unit in m) = Pressure head at section 1 (Unit in m) = pressure head at section 2 (unit in m) =

a) What is the head loss in (m)? b) What is the pressure drop (P1-P2) in (kPa)?