VERTICAL PARABOLIC CURVE IS TO CONNECT A BACK TANGENT OF -2% AND A FORWARD TANGENT OF 3%. THE CHANGE OF GRADE IS 0.20% PER 20M STATION. THE STATIONING OF PVC IS 15+210 WITH AN ELEVATION OF 100M. A.) FIND THE

Q: An equal-tangent vertical curve is to be constructed between grades of -3% and +2% (travelling left…

A: Given:- Downgrade of curve, g1 = -3% Upgrade of curve, g2 = +2% Station of PVI = 4 + 550.000…

Q: Vertical Curve: If L=1320 ft, the BVC is at 5+00, What is the Station and Elevation for PVI ? G1 is…

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Q: 3. For curve y + 4x2 - 12x , locate the possible maximum and minimum %D points.

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Q: 1. A grade of -3.7% grade intersects a grade of +2.80% at Station 11 + 488.00 of elevations 122.50…

A: G1 = -3.7% G2 = 2.8% PI Station = 11+488 PI elevation = 122.5 Vd (design velocity) = 60Km/h = 60…

Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance meters…

A: Using equation y=g2-g12Lx2+g1x+PVCelvg1=back tangentg2=Forward tangentL=length

Q: to 0.5%. gth of curve.

A: Length :L=Ar=(1.5+3)0.5×100=900m

Q: Problem 4 A vertical summit parabolic has its P.I. at station 12 + 750 with elevation of 77.30 m.…

A: Given Data:Station of PV1=12+750Elevation Pv1=77.30mForward Tangent g2=-3.8%back tangent…

Q: Q6/A grade gl of+ 1.23% intersects grade g2 of -2.75% at a vertex whose station 18+00 and elevation…

A: Given:- The gradient of first tangent = g1 = +1.23% The gradient of second tangent = g2 = -2.75%…

Q: A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an…

A: Given that   Sag vertical curve   g1 = -5%   g2 = 0   A = G1-G2   A = -5   PC station = (10+110)…

Q: A symmetrical parabolic curve passes through point A whose elevation is 23 23m at a distance of 54…

A: Correction in question:- As the elevation of PC is given as 22.56 m Hence, elevation of point A can…

Q: A-3.00% grade meets a +2.50% grade at station 4 + 200 and elevation 105.568 m, 200-m curve, stakeout…

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Q: A symmetrical vertical summit curve has tangents of +4.5% and -2.5%. The allowable rate of change of…

A: Question is based on the vertical summit curve . Tangents of curve,allowable rate of change of…

Q: SURVEYING 103 C2 Problem set: as An unsymmetrical parabolic curve has a forward tangent of-8% and…

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Q: Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a…

A: Given data, Two grade intersecting at station 1+250m g1=+6% and g2=-3% L=183m L1=121.95m and…

Q: the tangents of a sag curve connects at the point of intersection having station 18.424.35 and…

A: This question belongs to subject surveying. In this question we find out the value of the lowest…

Q: A vertical parabolic curve of length 180m has the following specifications. The point of interaction…

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Q: 10. A +2.8% grade at 1 + 200 is to be connected to a -4.2% grade at 1+600 using a symmetrical…

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Q: A 591m equal tangent crest vertical curve has PVC at Sta 19+252 and at elevation 124m. The initial…

A: Since this s an equal tangent vertical curve, distance from the center of the curve to the two…

Q: ration of the P.C. at station 4+100 is 22.5 e length of the curve is 120m.. Determin

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Q: Problem 3 The vertex is at station 12 + 200 and elevation 35 m. It is required to connect the two…

A: To use the equations for an unsymmetrical vertical parabolic curve. The general equation for the…

Q: forward tangent is -3.0%, and the location of the highest point elevation of the highest point is…

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Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: A vertical crest curve has an approach grade +3% and a departure grade –3%. The VIP level is 120 m…

A: To calculate 'H' based on the given data we have  2HL2= (g1 -g2)L2L g1 = 3% = 0.03 g2 = -3% = - 0.03…

Q: Problem 2 A symmetrical vertical summit curve has tangents of +5% and -3%. The allowable rate of…

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Q: as PVC at Sta 19+274 and at elevation 136m. The initial grade is 6.14% and the final grade is…

A: Given data PVC at Sta 19+274 elevation 136m  initial grade is 6.14% final grade is -5.58%

Q: CONNECT A FORWARD TANGENT OF 3% AND A BACK TANGENT OF-15% BY A 300 M SYMMETRICAL PARABOLIC CURVE. IT…

A: Given: The grade g1 is -15%. The grade g2 is 3%. The length of the curve is 300 m. The station at PI…

Q: locate both highest and lowest point in terms of horizontal distance from PVT station and difference…

A: Of location of  both highest and lowest point in terms of horizontal distance from PVT station and…

Q: tangent is -3.0%, and the location of the highes on of the highest point is 100 m. t is the Station…

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Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: 6. A symmetrical vertical summit curve has tangents of +4% and -2%. The allowable rate of change of…

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Q: A 524m equal tangent crest vertical curve has PVC at Sta 18+257 and at elevation 166m. The initial…

A: Given: The initial grade is 6.06%. The final grade is -3.71%. The length is 524 m. The PVC station…

Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: A-3.3% grade meets a +7.4% grade at a vertex (EI. 139.57m) directly under an overpass bridge having…

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Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Q: through point A whose elevation is 23.23m at a distance of 54 meters from P.C. The elevation of the…

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Q: It is required to construct a vertical curve with 400m from the PC at STA 3+16, elev.214m to the…

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Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.