A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the length of the curve? a. 120 m b. 123 m c. 121 m d. 122 m 2. What is the stationing of PT? a. 35+363 b. 35+362 c. 35+361 d. 35+360 3. What is the stationing of PC? a. 35+222 b. 35+221 c. 35+220 d. 35+223

A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the length of the curve? a. 120 m b. 123 m c. 121 m d. 122 m 2. What is the stationing of PT? a. 35+363 b. 35+362 c. 35+361 d. 35+360 3. What is the stationing of PC? a. 35+222 b. 35+221 c. 35+220 d. 35+223

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the stationing of PT? a. 35+363 b. 35+362 c. 35+361 d. 35+360
A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the elevation of PC? a. 194.60 m b. 196.40 m c. 196.60 m d. 194.40 m
3. A grade of +5% grade intersects a grade of -3.0% P.C.has a of 10 + 110.00 which has an elevation of 30MASL.These two center gradelines are to be connected by a240 meter symetrical vertical parabolic curve.What is the station of the highest point of the vertical curve.What will be the elevation of the curve at station 10+210What will be the elevation of the curve at station 10+250
A compound curve is laid out 480 m. from the P.C. to the P.C.C. having a radius of 763.94 m then from the P.C.C another curve was laid out to the P.T. 250 m long with a radius of 208.85 m. If the stationing of the point of intersection of the tangents is 10 + 432.25. a. Determine the stationing of the P.C b. Determine the length of the long chord from the P.C. to the P.T. c. Determine the angle that the long chord makes with the tangent
3. A grade of +5% grade intersects a grade of -3.0% P.C. has a of 10 + 110.00 which has an elevation of 30MASL. These two center gradelines are to be connected by a 240 meter symetrical vertical parabolic curve. What is the station of the highest point of the vertical curve. What will be the elevation of the curve at station 10+210 What will be the elevation of the curve at station 10+250
A grade of +5% grade intersects a grade of -3.0% P.C. has a of 10 + 110.00 which has an elevation of 30MASL. These two center gradelines are to be connected by a 240 meter symetrical vertical parabolic curve. a. What is the station of the highest point of the vertical curve. b. What will be the elevation of the curve at station 10+210. c. What will be the elevation of the curve at station 10+250
A -6% grade and a +2% grade intersect at STA 12+200 whose elevation is at 25.632m. Two grades are to be connected by a parabolic curve, 160m long. A. Find the grade of the first quarter point on the curve. In decimal form B. Find the stationing of the lowest point of the curve.
A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass through a point, p, the stationing of which is 35 + 280 and the elevation is 198.13 m. If the elevation of the grade intersection is 200 m. with stationing 35 + 300, 1. Determine the length of the curve. a. 120 m b. 167 m c. 234 m d. 436 m 2. Determine stationing of P.C. a. 35 + 260 b. 35 + 240 c. 35 + 160 d. 35 + 120 3. Determine elevation of P.C. a. 324.30 m b. 167.40 m c. 523.40 m d. 196.40 m 4. determine the location of the highest point on the curve from P.C. a. 84 m b. 57 m c. 72 m d. 66 m 5. determine elevation of station 35 + 260 on the curve.. a. 132.43 m b. 157.85 m c. 197.43 m d. 162.46 m
A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass through a point, p, the stationing of which is 35 + 280 and the elevation is 198.13 m. If the elevation of the grade intersection is 200 m. with stationing 35 + 300. Length of Curve= 120m Stationing of P.C.= 35 + 120 1. Determine elevation of P.C. a. 324.30 m b. 167.40 m c. 523.40 m d. 196.40 m 2. determine the location of the highest point on the curve from P.C. a. 84 m b. 57 m c. 72 m d. 66 m 3. determine elevation of station 35 + 260 on the curve.. a. 132.43 m b. 157.85 m c. 197.43 m d. 162.46 m
3. A -9% grade meets a +5% grade at station 2+123.56 of elevation 55.56 m. The lengths areunequal L1=100 m, L2=80 m. Calculate the elevation at every full station. Compute thestationing and elevation of the lowest point on the curve.
3. A grade g1 of +3.25% intersects grade g2 of -2.75% at a vertex whose station and elevation are STA 257+17.65 and 3,820.14 ft, respectively. An equal-tangent parabolic curve 900 ft long has been selected to join the two tangents. a. Compute the station and elevation of PVC. b. Compute the station and elevation of the first full station inside the curve. c. Identify the station and elevation of the highest point on the curve.
Problem No. 1: Two tangents intersect at STA 2+550. A compound curve laid on their tangents has the following data: I1=31deg.;I2=36deg.;D1=3deg.;D2=5deg.; (a) Compute the stationing at PC,PCC and PT