A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance meters from P.C. The elevation of the P.C. at station 4+100 is 22.56m. The grade of the back ta is +2% and the length of the curve is 120m.. Determine the grade of the forward tangent. -2.3%

A parabolic curve JS 400 m long connects two tangent grades of +6.4% and -3.4%. If the elevation of the summit is 262 m, what is the elevation of point S?

Q3:- A parabolic vertical curve joins a grade of -3% to a grade of +5.5 %. The PVI is at station 3+51 and its elevation is 34.11m. The curve passes under a bridge at station 3+76. The elevation of the bottom of the bridge is 41.0 m; determine the required length of the curve if the minimum vertical clearance under the bridge is 4.8m?

A vertical sag parabolic curve has a length of curve of 420 m. from A to B. The back tangent has a slope of −3.2% and the point of intersection of the tangents is at station 7 + 180 with an elevation of 998 m. Find the elevation of point A.

Q- A vertical summit curve is formed at the intersection of two gradients. +5% and −5%. The length of summit curve needed to provide a stopping sight distance of 100 m will be

A symmetrical parabolic curve passes throughpoint A whose elevation is 23.33m at a distance of 54mfrom the PC. The elevation of the PC at station 4+100 is22.56m. The grade of the back tangent is +2% and thelength of the curve is 120m.5. Determine the grade of the forwardtangent.6. Determine the stationing of the highestpoint of the curve.

Sag Curve: A grade from the PVC to the PVI is -6% and from PVI to PVT is +2%. It is required to connect these grade lines with a vertical parabolic curve will pass 3.0 m. directly above the PVI. 11. Determine the length of this curve. a) 420 m b) 380 m c) 400 m d) 300 m 12. Determine the location of the lowest point measured from the PVT. a) 100m b) 75m c) 100m d) 225m 13. Compute the vertical offset at a point on the curve 100m from the PVC. a) 2.45m b) 2.33m c) 1.56m d) 1.33m

SURVEYING 3B