V = Ve/RC (discharging). (21.80) capacitor Von V - 0.368V. 0 T= RC 2r 3r 4r Switch (a) (b) Figure 21.39 (a) Closing the switch discharges the capacitor C through the resistor R . Mutual repulsion of like charges on each plate drives the current. (b) A graph of voltage across the capacitor versus time, with V = Vo at t = 0. The voltage decreases exponentially, falling a fixed fraction of the way to zero in each subsequent time constant t.
V = Ve/RC (discharging). (21.80) capacitor Von V - 0.368V. 0 T= RC 2r 3r 4r Switch (a) (b) Figure 21.39 (a) Closing the switch discharges the capacitor C through the resistor R . Mutual repulsion of like charges on each plate drives the current. (b) A graph of voltage across the capacitor versus time, with V = Vo at t = 0. The voltage decreases exponentially, falling a fixed fraction of the way to zero in each subsequent time constant t.
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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A heart defibrillator is used to resuscitate an accident victim by discharging a capacitor through the trunk of her body. A simplified version of the circuit is shown . (a) What is the time constant if an 8.00-μF capacitor is used and the path resistance through her body is 1.00×103 Ω ? (b) If the initial voltage is 10.0 kV, how long does it take to decline
to 5.00×102 V ?
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