Using values from Appendix C of your textbook, calculate the value of Keq at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCI(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 X (c) 4 NH3(g) + O₂(g) ⇒2 N₂H4(9) + 2 H₂O(1) Keq = 5.51e15

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.75QE
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Using values from Appendix C of your textbook, calculate the value of Keg at 298 K for each of the following reactions:
(a) Fe₂O3(s) + 6 HCl(g) 2 FeCl3(s) + 3 H₂O(g)
Keq = 9.47e6
(b) N₂(g) + O₂(g) = 2 NO(g)
Keq = 1.75e-31
x.
(c) 4 NH3(g) + O₂(g) 2 N₂H₂(g) + 2 H₂O(1)
Keq = 5.51e15
Transcribed Image Text:Using values from Appendix C of your textbook, calculate the value of Keg at 298 K for each of the following reactions: (a) Fe₂O3(s) + 6 HCl(g) 2 FeCl3(s) + 3 H₂O(g) Keq = 9.47e6 (b) N₂(g) + O₂(g) = 2 NO(g) Keq = 1.75e-31 x. (c) 4 NH3(g) + O₂(g) 2 N₂H₂(g) + 2 H₂O(1) Keq = 5.51e15
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