Using the t-table, find the critical values for a two-tailed test with an α = 0.01 for a sample size of 18.

14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean  The null and alternative hypotheses would be:     Ho: ? μ p  Select an answer = ≠ > <   (please enter a decimal)    H1: ? p μ  Select an answer < > = ≠   (Please enter a decimal) The test statistic ? t z  =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is ? > ≤  αα Based on this, we should Select an answer reject fail to reject accept  the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…

When using an independent samples t-test, the author of a journal article reported that t(30) = 3.60, p < .05. Should the researcher reject the null or fail to reject the null?

Find the standardized test statistic t for a sample with n = 20, x=6.8, s= 2.0, and o = 0.05 if Hau < 7.2, Round your answer to three decimal places.

Find the critical value tc for the confidence level c=0.80 and sample size n=28.

Using the z table, find the critical value (or values) for an α = .09 two-tailed test.

You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.72. You use a significance level of α=0.02      H0:p=0.72      H1:p<0.72You obtain a sample of size n=291n=291 in which there are 192 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72. There is not sufficient evidence to warrant rejection of the claim that the accuracy rate for fingerprint identification is less than 0.72. The sample data support the claim that the…

Using the t-table, find the critical value for a left-tailed test with an α = 0.05 for a sample size of 23.

(b) For a one-tailed test using the t-distribution, if the sample size is 20, find out the critical values based on the given significance levels: (1) a = 0.1, (2) a = 0.05, and (3) a = 0.01.