14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14% The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14%. The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 14%. Interpret the p-value in the context of the study. If the sample proportion of inner city residents who have sleep apnea is 12% and if another 359 inner city residents are surveyed then there would be a 13.47% chance of concluding that fewer than 14% of inner city residents have sleep apnea. There is a 14% chance of a Type I error If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 13.47% chance fewer than 12% of the 359 residents surveyed have sleep apnea. There is a 13.47% chance that fewer than 14% of all inner city residents have sleep apnea. Interpret the level of significance in the context of the study. If the population proportion of inner city residents who have sleep apnea is smaller than 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 14%. There is a 5% chance that the proportion of all inner city residents who have sleep apnea is smaller than 14%. There is a 5% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth. If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is smaller than 14%.

14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14% The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14%. The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 14%. Interpret the p-value in the context of the study. If the sample proportion of inner city residents who have sleep apnea is 12% and if another 359 inner city residents are surveyed then there would be a 13.47% chance of concluding that fewer than 14% of inner city residents have sleep apnea. There is a 14% chance of a Type I error If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 13.47% chance fewer than 12% of the 359 residents surveyed have sleep apnea. There is a 13.47% chance that fewer than 14% of all inner city residents have sleep apnea. Interpret the level of significance in the context of the study. If the population proportion of inner city residents who have sleep apnea is smaller than 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 14%. There is a 5% chance that the proportion of all inner city residents who have sleep apnea is smaller than 14%. There is a 5% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth. If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is smaller than 14%.

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Description: 14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be conclu

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For this study, we should use Select an answer z-test for a population proportion t-test for a population mean
The null and alternative hypotheses would be:
Ho: ? μ p Select an answer = ≠ > < (please enter a decimal)
H₁: ? p μ Select an answer < > = ≠ (Please enter a decimal)

The test statistic ? t z = (please show your answer to 3 decimal places.)
The p-value = (Please show your answer to 4 decimal places.)
The p-value is ? > ≤ αα
Based on this, we should Select an answer reject fail to reject accept the null hypothesis.
Thus, the final conclusion is that ...
- The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14%
- The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 14%.
- The data suggest the population proportion is not significantly smaller than 14% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 14%.
Interpret the p-value in the context of the study.
- If the sample proportion of inner city residents who have sleep apnea is 12% and if another 359 inner city residents are surveyed then there would be a 13.47% chance of concluding that fewer than 14% of inner city residents have sleep apnea.
- There is a 14% chance of a Type I error
- If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 13.47% chance fewer than 12% of the 359 residents surveyed have sleep apnea.
- There is a 13.47% chance that fewer than 14% of all inner city residents have sleep apnea.
Interpret the level of significance in the context of the study.
- If the population proportion of inner city residents who have sleep apnea is smaller than 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 14%.
- There is a 5% chance that the proportion of all inner city residents who have sleep apnea is smaller than 14%.
- There is a 5% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.
- If the population proportion of inner city residents who have sleep apnea is 14% and if another 359 inner city residents are surveyed then there would be a 5% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is smaller than 14%.

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