Using the graph data I estimated Slope = 2.8, about the same as the steeper part of the maternal hemoglobin, does this represent a strong positive cooperativity between enzyme subunits?

14)  Calculate K’eq and ΔG’0 for the following: A 0.1 M solution of glucose 1-phosphate at 25oC is incubated with a catalytic amount of phosphoglucomutase, the glucose 1-phosphate is transformed to glucose 6-phosphate.  At equilibrium, the concentrations of the reaction components are Glucose 1-phosphate (4.5 X 10-3 M) and Glucose 6-phosphate (9.6 X 10-2 M).

The Nutrition Facts label on most food products shows % daily values based on a food energy requirement of 8,360 kJ (2,000 kcal) at normal resting state. a) Assuming that the efficiency of converting food energy to ATP is 50%, calculate the mass of ATP (in kg) that is harvested daily by the human body from 8,360 kJ of food energy. A total of 30.5 kJ of energy is needed to synthesize one mole of ATP under standard conditions. The molar mass of ATP is 505 g/mol. b) For an average 68-kg (150 lbs.) human adult, calculate the % mass of extracted ATP (from your answer in 2a) relative to body weight.

The transport of aspirin (pKa = 3.5, structure shown here) from the digestive tract to the circulation occurs by nonmediated absorption into cells lining the stomach (where pH = 0.8) and the small intestine (where pH 6.0). Do you expect absorption to be faster in the stomach or in the small intestine?

Consider a protein with two surface-exposed histidine residues: HisA is a “typical” histidine residue with a pKa = 6.2 HisB is involved in a stabilizing interaction (His-NH+ ..... -O2C-Glu) with a neighboring glutamic acid residue. For HisB, the Gibbs free energy of deprotonation at pH = 7.0 and T = 293K is ΔG'o = +15 kj mol-1. If you had a solution, at pH = 7.0 and T = 293K, containing this protein: a) What fraction of HisA residues are protonated? b) What fraction of HisB residues are protonated? c) What is the pKa of HisB?

5.50 1/V, min/umol 5.00 4.50 4.00 y = 0.9474x + 2.6649 y = 0.9997x + 2.032 0.00 1.00 2.00 2.50 3.00 1/[S], uM -1 Looking at the double reciprocal plot for an enzyme in the absence of inhibitor and in the presence of two concentrations of inhibitor, what would be the Vmax for the uninhibited enzyme? (bottom graph) Equation is given. Choose the one best answer. 3.50 3.00 2.50 2.00

The last residue of the protein (tail) is Tryptophan, and the first residue (head) is labeled with IAEDANS acceptor. Estimate the length of the protein (head to tail) if the efficiency of RET measures at 0.01 Please show step by step and how to get the 34.014 number

In a pUC19 digest for 1 ug of pUC19 (DNA conc. 282ng/ul) using 10X Cutsmart buffer, pure water and BamHI enzyme in a total volume of 40 ul, how much of each solution is added to the total volume?

The KM of a Michaelis-Menten enzyme for a substrate is 1.0 x 104 M. At a substrate concentration of 0.20 M, v = 43 μmol/min. Calculate the rate of reaction when the substrate concentration is tenfold lower, 0.020M. 43 μmol min rate of reaction → Vmax Км substrate concentration →

Calculate θ for a certain protein-ligand pair when the ligand concentration = 1 M and the Kd = 1 X 10-15 M.