Use the following sample to estimate a population mean .5679.38685.880.579.981.581.18196.4Assuming the population is normally distributed, find the 99.5% confidence interval about the populationmean. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places.99.5% C.I. =

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Answered: Use the following sample to estimate a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2.5 A confidence interval estimate is constructed around a. the degree of confidence b. the population parameter C. the population mean d. the point estimate 2.6 The z value that is used to construct a 95% confidence interval is: a. 2,58 b. 1.65 C. 1.96 d. 1.28 2.7 Which of the following is NOT a property of the student'st distribution? a. It's exact shape (i.e., spread) is characterized by the degrees of freedom b. It is symmetric c. All of the above are properties of the t distribution d. As the sample size grows, it gradually approaches the normal distribution
Sample data set: 47 95 54 33 64 4 8. 57 80 8 90 3. 49 4 44 79 80 48 16 68 7 15 21 78 109 40 50 29 Estimate the mean with 92% confidence. Round answer to one decimal place. 9, 6.
7.1.13 !E Question Help Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1034 and x= 559 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)
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Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
K You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 35 home theater systems has a mean price of $131.00. Assume the population standard deviation is $15.50. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (). (Round to two decimal places as needed.) W
To build a 95% CI for the mean of a population, you take a random sample and find these values: 18.4 19.8 17 18.6 23 21.7 18.9 14.3 17.6 21.2 21.4 23.4 20 20.7 15.2 21.9 21 What is the CI? Enter like this: (min,max) Be sure to use the parentheses or you will be marked wrong. Keep at least 3 decimals in all intermediate steps, and round your answer to two decimals. Submit Question
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
You are interested in finding a 95% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 8 19 14 10 5 15 20 5 27 26 a. To compute the confidence interval use a ? v distribution. b. With 95% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.
Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).99% C.I. =
K In a random sample of eleven people, the mean driving distance to work was 22.3 miles and the standard deviation was 4.9 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. It can be said that % of the population has a driving distance to work (in miles) that is between the interval's endpoints. O B. % of all random samples of eleven people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. OC. With % confidence, it can be said that most driving distances…
70 students are asked in a survey how many hours they work during a week. Their responses have a mean of 17 hours and a standard deviation of 2 hours. Find the margin of error for a 80% confidence interval. Round your answer to two decimal places. hours

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