You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 11 randomly selected college students. Round answers to 3 decimal places where possible. 1 9 8 4 2 9 8 4 11 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of days of class that college students miss is between and days. c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of missed class days and about percent will not contain the true population mean number of missed class days.

You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible.   18 6 28 15 15 16 9 8 28 15 17   a. To compute the confidence interval use a    distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between  and   visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.

You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible.   18 12 10 9 15 5 9 6 18 5 17 11 6   a. To compute the confidence interval use a     distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between  and   visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About  percent of these confidence intervals will contain the true population mean number of visits per patient and about  percent will not contain the true population mean number of visits per patient.

You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 12 randomly selected physical therapy patients. Round answers to 3 decimal places where possible.   25 14 23 8 6 15 18 5 8 17 9 7   a. To compute the confidence interval use a ? z t Correct distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between blank and  blank visits. c. If many groups of 12 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About # percent of these confidence intervals will contain the true population mean number of visits per patient and about # percent will not contain the true population mean number of visits per patient.

You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 15 randomly selected physical therapy patients. Round answers to 3 decimal places where possible.   8 15 5 18 9 28 5 14 23 25 18 20 23 9 16   a. To compute the confidence interval use a    distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between  and   visits. c. If many groups of 15 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ____percent of these confidence intervals will contain the true population mean number of visits per patient and about ____percent will not contain the true population mean number of visits per patient.

You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible.   27 5 28 22 15 9 16 10 25 18 5   a. To compute the confidence interval use a   Z OR T   distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between  ?  and   ? visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About  ? percent of these confidence intervals will contain the true population mean number of visits per patient and about  ? percent will not contain the true population mean number of visits per patient.

Next Question A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and w that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b ley weighed 9.3, 9.1, 9.5, and 9.6 pounds. D Assume below. a. Choose the correct interpretation of the confidence interval below and, if necessary, fill in the answer boxes to complete your choice. O A. We are 95% confident that the sample mean is between and O B. There is a 95% chance that all intervals will be between and O C. We are 95% confident the population mean is between and O D. The requirements for constructing a confidence interval are not satisfied. (Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.) b. Does the interval capture 10 pounds? Is there enough evidence to reject the null hypothesis that the population mean weight is 10 pounds? Explain…

If we find a 95% confidence interval using a sample, then we can say... 95% of individuals will fall on that interval there is a 5% chance the population proportion is NOT on the interval. 95% of our samples will fall on that interval. No answer text provided.

You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible.   18 18 27 17 15 7 11 15 9 12 19 a. With 98% confidence the population mean commute for non-residential college students is between _____  and____miles. b. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About (____)  percent of these confidence intervals will contain the true population mean number of commute miles and about(_____)   percent will not contain the true population mean number of commute miles.

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.