Use the following information to answer the next two questions. In cattle, a polled or hornless trait (P) is dominant over a horned trait(p). A polled bull mated with three different cows, and the following calves were born in the spring. Cow Phenotype F1 Generation Phenotype Cow 1 - Horned Calf 1 - Horned Cow 2 - Polled Calf 2 - Horned Cow 3 - Polled Calf 3 - Polled Which of the following rows correctly identifies the genotypes of the cattle? Select one: a. Bull - Pp Calf 2 - pp b. Cow 3 - Pp Calf 3 - pp c. Cow 2 - pp Calf 1 - Pp d. Cow 1 - pp Bull - PP

Please read the scenario below, and then answer the question (in bold) that follows. In cats, the allele (B) produces a black coat color and the allele (b) produces a yellow coat color. These alleles are incompletely dominant to each other. A heterozygote produces a tortoise shell coat color. The alleles (B) and (b) are also sex-linked (i.e., they are carried on the X chromosome), and cats possess an XX-XY sex determination system, like humans. If a female cat with a tortoise shell coat mated with a male cat who had a yellow coat... What percentage of their offspring will have tortoise shell coats?   a. 0%   b. 25%   c. 50%   d. 75%   e. 100%

PLEASE DO BAR GRAPHS BASED ON DATA: Procedure: Assuming both parents carry three tall genes and three short genes, you will model the inheritance of height for ten different offspring. Flip a coin six times to determine how many tall and short genes the child inherits. Heads represents a tall gene and tails represents a short gene. Record all of your data along with the class data in the tables below   Data: Table 1: Group results   Flip (Your Group)          1              2     3     4    5 Number of tails  0  1  2  3  4 Number of heads  6  5  4  3  2   Table 1: continued    Flip (Your Group)    6    7      8     9    10 Number of tails  5  6  3  2  1 Number of heads  1  0  3  4  5   Table 2: Group and class results Flip  Situation 0 T 6 H 1 T  5 H 2 T  4 H 3 T  3 H 4 T  2 H 5 T  1 H 6 T  0 H Your Group Total  1  3  6  10  9  5  1 Class Total    0…

For the following five questions, A = true, and B = false 18. (2 pts) The dominance of an allele may vary for different traits. 19. (2 pts) Loss-of-function alleles are recessive, not dominant. 20. (2 pts) A haplosufficient allele is able to produce a wild-type phenotype in the heterozygous state. 21. (2 pts) The permissive temperature, which is usually lower than the normal growth temperature, is the temperature at which a mutant phenotype becomes observable. 22. (2 pts) In a cross between two true-breeding recessive mutants that are affected in different genes, the proportion of F1 progeny that show complementation (the wild-type phenotype) is affected by the map distance between the two genes.

Human blood type is regulated by 3 alleles (A,B,O). Four blood types are possible: A, B, AB, and O.  A woman who has blood type A has a son with blood type O. She sues Man #1, whom she claims to be the father, for child support.  Man #1 suspects he is not the only paternal candidate and requests blood-typing for Man #2. Based on the blood-typing results in the table below who could be the father? Man #1: Type B Man #2: Type O Man #1 only Man #2 only Man #1 or Man #2 Impossible for either, since the Mother has blood type A

Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the genotype aabbCcDDEe, want to have children. Assume each locus follows Mendelian inheritance patterns for dominance. What proportion of the offspring will have each of the specified characteristics? Round your answers to two decimal plates. same genotype as the father: TOOLS x10 phenotypically resemble the father: phenotypically resemble neither parent: same genotype as the mother: phenotypically resemble the mother:

For n = number of genes segregating, how many different phenotypes and genotypes are observed in the F2 generation? Assume complete dominance at each gene. 2" phenotypes and 3" genotypes 3" phenotypes and 2" genotypes n2 phenotypes and n° genotypes n3 phenotypes and n2 genotypes

Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below.  Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.

A scientist is investigating the inheritance of two autosomal recessive genes in rat, ear length (long is dominant to short) and fur color (gray is dominant to white). The table below provides the number of observed off-spring for each phenotype, when heterozygous rats are crossed.  What are the expected values for each phenotype? Phenotype Observed Expected Long, gray 189   Long, white 56   Short, gray 74   Short, white 23   Total 342

Please follow instructions from pic above Red roan hair colour in some horses is due to codominance of the white allele and the red allele. If a red roan horse mates with a white horse, indicate the genotypic and phenotypic ratios that would result.