Background:   In certain types of cattle, three colors exist: white (WW), white hairs red hair (RR), red hairs roan (RW), a mixture of red and white hairs Roan is a codominant condition.   Question:   A breeder wants to only produce roan-colored cattle. Which of the following parents should she select to only produce roan-colored offspring? Select all that apply.   a black-haired parent b white-haired parent c roan-haired parent d red-haired parent

Labrador retrievers are commonly black, brown, or yellow. Two different genes determine coat color in Labrador retrievers. The B gene determines pigment color (B is black, bb is brown). The E gene determines whether the pigment can be deposited in the hair shaft: ee prevents any pigment from being deposited, resulting in yellow dogs. You want to breed Labrador retrievers, and you cross a true-breeding brown Labrador retriever to a true-breeding yellow Labrador retriever. All 15 of the F1 puppies are black. After the puppies grow up, you cross two of the F1 black dogs together. In the F2 generation you get 8 black puppies, 4 yellow puppies, and 3 brown puppies. Part 1 What is/are the possible genotype(s) of the true-breeding brown lab in the P generation? O bbEE Brown bbee O bbEe Could be either answer bbEE or bbEe Part 2 What is/are the possible genotype(s) of the true-breeding yellow lab in the P generation? Obbee Bbee BBee Could be either bbee or Bbee. O Could be either Bbee or BBee.…

A family tree of sorts is called a pedigree. The symbols used for a pedigree are: female, unaffected female, affected ☐male, unaffected male, affected I 11 III 1 Pedigree Chart Minor Peta #2 Siblings are placed in hirth order from left to right and are labeled with Arabic numerals. Each generation is labeled with a Roman numeral. Therefore, the male exhibiting the trait in the pedigree below in the bottom, center would be identified as III-4. 1. Which members of the family above are affected by Huntington's Disease? 4. How many girls did II-1 and 11-2 have? 3. How many children did individuals 1-1 and 1-2 have? 2. There are no carriers for Huntington's Disease- you either have it or you don't. With this in mind, is Huntington's disease caused by a dominant or recessive trait? 5. How are individuals III-2 and II-4 related? 8 -Huntington's Disease

A cross is performed between a pure-breeding pea plant with round and yellow seeds and a pure-breeding pea plant with wrinkled and green seeds. All F1 progeny have round and yellow seeds. The F1 plants are self-crossed. The following results are observed in the resultant F2 generation: 65 round and yellow, 42 round and green, 50 wrinkled and yellow, and 45 wrinkled and green. Use a Chi Square analysis to determine whether these traits follow Mendel’s law of independent assortment. Show all calculations

In domestic chickens, feather color is inherited as an incompletely dominant trait.  Feather color is inherited as:  BB= Black          Bb= Speckled              bb= White What are the predicted phenotypes and their frequencies for each of the following crosses?  A. BB rooster x white hen         Black         ___________                 Speckled ___________ White       ___________   B. Speckled rooster x speckled hen         Black         ___________  Speckled ___________ White       ___________     C. Speckled rooster x white hen         Black         ___________  Speckled ___________ White       ___________

For the following problem: Identify the gametes for each parent, build a Punnett Square of the probability of offspring. Show the resulting genotype ratios and the resulting phenotype ratios. The submission file on Canvas will typically have a multiple-choice component or may be a fill-in-the-blank question related to genotype and/or phenotype outcomes. Be prepared to address all of these details in the questions. a )In Pansy flowers, a gene for follower color is “incompletely dominant”. All flowers resulting from the cross of a homozygous red (R) flowering plant with a homozygous white (r) flowering plant were pink. If a pink-flowering plant is bred with another pink-flowering plant, determine the probable genotype and phenotype ratios of the offspring. b) The ratio of genotypes is ________________ .c) The ratio of phenotypes (red:pink:white) is ______________.

Answer only number 2

Place each box in the appropriate column. (Each box is used only once.) Phenotypic ratio of the progeny will be 1:1. Probability of an ss Rr offspring is 25%. SS Rr x SS rr The chance of Ss Rr offspring is 25%. Probability of an SS offspring is 100%. Probability of an SS Rr offspring is 50%. Probability of offspring homozygous recessive for the R gene is 25%. Ss RR x Ss rr Genotypic ratio of the progeny will be 1:2:1. Phenotypic ratio of the progeny will be 9:3:3:1. Ss Rrx Ss Rr

In lilies, large lilies are dominant to small ones and green ones are dominant to white ones. You cross two lilies heterozygous for both traits and receive the following results: 206 Large, green lilies 83 Large, white lilies 65 Small, green lilies 30 Small, white lilies Using chi square analysis, determine the chi square value, degrees of freedom, and if this outcome fits the expected phenotypic ratio (use p<0.05). Percentage Points of the Chi-Square Distribution Degrees of Probability of a larger value of x? Freedom 0.99 0.95 0.90 0.75 0.50 0.25 0.10 0.05 0.01 1 0.000 0.004 0.016 0.102 0.455 1.32 2.71 3.84 6.63 2 0.020 0.103 0.211 0.575 1.386 2.77 4.61 5.99 9.21 3 0.115 0.352 0.584 1.212 2.366 4.11 6.25 7.81 11.34 4 0.297 0.711 1.064 1.923 3.357 5.39 7.78 9.49 13.28 0.554 1.145 1.610 2.675 4.351 6.63 9.24 11.07 15.09 6. 0.872 1.635 2.204 3.455 5.348 7.84 10.64 12.59 16.81 7 1.239 2.167 2.833 4.255 6.346 9.04 12.02 14.07 18.48 8 1.647 2.733 3.490 5.071 7.344 10.22 13.36 15.51 20.09 9…

Dihybrid crosses and must show the Punnet square