Use the critical value method to test the null hypothesis Ho: B₁=0 versus H₁ : B₁ #0. Use the a=0.05 level of significance.

The test statistic of z = 0.53 is obtained when testing the claim that p > 0.5. Identify the hypothesis test as being​ two-tailed, left-tailed, or​ right-tailed. Find the​ P-value. Using a significance level of α = 0.05​, should we reject H0 or should we fail to reject H0​?

Test the claim that the mean GPA of night students is larger than 3.2 at the .005 significance level.The null and alternative hypothesis would be: H0:p=0.8H1:p<0.8 H0:p=0.8H1:p>0.8 H0:μ=3.2H1:μ>3.2 H0:μ=3.2H1:μ≠3.2 H0:μ=3.2H1:μ<3.2 H0:p=0.8H1:p≠0.8 Based on a sample of 55 people, the sample mean GPA was 3.22 with a standard deviation of 0.03The test statistic is  (to 3 decimals)The critical value is  (to 3 decimals)Based on this we fail to reject the null hypothesis reject the null hypothesis

Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.

Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.10 significance level.The null and alternative hypothesis would be:   H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is:   right-tailed left-tailed two-tailed The sample consisted of 55 night students, with a sample mean GPA of 2.32 and a standard deviation of 0.05, and 55 day students, with a sample mean GPA of 2.37 and a standard deviation of 0.02.The test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be:   H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is:   two-tailed right-tailed left-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 40 women, 40% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Check AnswerQuestion 14

Previously, 12.1% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 80 workers and finds that 18 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the x = 0.1 level of significance. What are the null and alternative hypotheses? P = 0.121 versus H1: p Ho: p (Type integers or decimals. Do not round.) > 0.121 Because npo (1- Po) = < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be:   H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is:   right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

A student performs a test of Ho p = 0.75 versus H, p < 0.75 at the a = 0.05 significance level and gets a P-value of 0.22. The student writes: 'Because the P-value is large, we accept Ho. The data provide convincing evidence that the null hypothesis is true." What should the student have written for their conclusion? Because the P-value is large, we fail to reject Ho. The data do not provide convincing evidence that the alternative hypothesis is true. O Because the P-value is large, we fail to reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Becaus the P-value is small, we reject Ho. The data provide convincing evidence that the alternative hypothesis is true. Because the P-value is large, we accept Ho. The data do not provide convincing evidence that the alternative hypothesis is true. What the student wrote is correct.

Test the claim that the mean GPA of night students is smaller than 2.5 at the 0.01 significance level.The null and alternative hypothesis would be:   H0:p=0.625H0:p=0.625H1:p≠0.625H1:p≠0.625 H0:p≥0.625H0:p≥0.625H1:p<0.625H1:p<0.625 H0:μ≤2.5H0:μ≤2.5H1:μ>2.5H1:μ>2.5 H0:μ≥2.5H0:μ≥2.5H1:μ<2.5H1:μ<2.5 H0:p≤0.625H0:p≤0.625H1:p>0.625H1:p>0.625 H0:μ=2.5H0:μ=2.5H1:μ≠2.5H1:μ≠2.5 The test is:   right-tailed two-tailed left-tailed Based on a sample of 35 people, the sample mean GPA was 2.48 with a standard deviation of 0.03The test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis