Test the claim that the proportion of men who own cats is smaller than 40% at the .10 significance level. The null and alternative hypothesis would be:   H0:p=0.4 H1:p<0.4 Based on a sample of 100 people, 39% owned cats The test statistic is:                                                    (to 2 decimals) The critical value is:                                                   (to 2 decimals)

Suppose ?1 and ?2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. Use the two-sample t test at significance level 0.01 to test H0: ?1 − ?2 = −10 versus Ha: ?1 − ?2 < −10 for the following data:  m = 8, x = 114.8, s1 = 5.01, n = 8, y = 129.9, and s2 = 5.35. Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.)

A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- E

Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x=102.2​, y=100.8​, r=0.854​, ​P-value=​0.000, and y=24.13+0.75x​, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 95​? Use a significance level of 0.05.   LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is nothing.

A medical equipment manufacturer believes that the proportion of faulty blood pressure monitors is greater than 0.11, the proportion stated by the supplier. We perform a hypothesis test at a significance level of 0.05 with the null and alternative hypothesis as follows: Ho: p = 0.11 and Ha: p < 0.11. A researcher inspects 150 items and finds 25 faulty ones. She gives a p-value of 0.01 in her analysis. Which of the following definitions is the correct interpretation of the p-value? O The probability of getting 25 or more faulty blood pressure monitors out of 150 if the true faulty rate is 0.11. The value that the z-statistic must be less than in order to reject the null hypothesis. The probability of rejecting a true null hypothesis. O The probability that the true rate of faulty items is 0.01.

The recidivism rate for convicted sex offenders is 9%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 396 convicted sex offenders who were also drug addicts, 51 of them became repeat offenders. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Но: 0.09 |(please enter a decimal) H1: P 0.09 (Please enter a decimal) c. The test statistic ? 2.697 (please show your answer to 3 decimal places.) d. The p-value =| 0.0035 v (Please show your answer to 4 decimal places.) e. The p-value is f. Based on this, we should reject the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton proportion is significantly higher than 9% at a = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat…

A random sample of n1 = 299 voters registered in the state of California showed that 146 voted in the last general election. A random sample of n2 = 211 registered voters in the state of Colorado showed that 120 voted in the most recent general election. Do these data indicate that the population proportion of voter turnout in Colorado is higher than that in California? Use a 5% level of significance. I need help with the wrong ones. level of Significance: .05 | H0: p1 = p2; H1: p1 < p2 |

You wish to test the following daim (Ha) at a significance level of a = 0.001. H.:P1 2 P2 Ha:P1 < P2 You obtain a sample from the first population with 244 successes and 117 failures. You obtain a sample from the second population with 523 successes and 202 failures. test statistic = [three decimal accuracy] p-value = [four decimal accuracy) The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null hypothesis O fail to reject the null hypothesis As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.

The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance.    one-tailed or two-tailed test:  State the hypotheses: df= tα or t value for the critical region =  sM =    t (test statistic)= Decision:

Test the claim that the proportion of men who own cats is smaller than 40% at the .005 significance level. The null and alternative hypothesis would be: