Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: H0:pM=pFH0:pM=pF H1:pMμFH1:μM>μF H0:pM=pFH0:pM=pF H1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μF H1:μM≠μFH1:μM≠μF The test is: right-tailed two-tailed left-tailed Based on a sample of 80 men, 25% owned cats Based on a sample of 80 women, 30% owned cats The test statistic is:  (to 2 decimals) The positive critical value is:  (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

In 1990, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephone company wants to perform a significance test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. The hypotheses are:                                H0: μ = 9.4 minutes                                HA: μ ≠ 9.4 minutesSuppose that the results of the sample lead to non-rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. Choose the best asnwer below:    A. Neither B. Type I error C. Type II error D.No error

Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.

Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.10 significance level.The null and alternative hypothesis would be:   H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is:   right-tailed left-tailed two-tailed The sample consisted of 55 night students, with a sample mean GPA of 2.32 and a standard deviation of 0.05, and 55 day students, with a sample mean GPA of 2.37 and a standard deviation of 0.02.The test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Test the claim that the proportion of men who own cats is larger than 24% at the .025 significance level. The null and alternative hypothesis would be: Ho:p = 0.24 Ho: = 0.24 Ho: u = 0.24 Ho:p = 0.24 Ho:u = 0.24 Ho:p 0.24 H1:p 0.24 H1:µ > 0.24 H1:µ # 0.24 H:p 0.24 The test is: right-tailed two-tailed left-tailed ㅇ Based on a sample of 60 people, 16 2/3% owned cats The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Submit Question • Previous DEC 11 étv

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level. The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 45% owned catsBased on a sample of 40 women, 70% owned cats The test statistic is:  (to 2 decimals) The positive critical value is:  (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

A researcher wants to test whether the mean height for men and women are different, using a significance level of 0.05. Which is the correct hypothesis? A Ho: P1 = P2 Ha: P1 P2 D Ho: P1 = μ2 Ha: H1 H2 O C A OF OE O B B Ho: P1 = P2 Ha: P1 P2 E Ho: P1 = μ2 Ha: 12 C Ho: P1 = P2 Ha: 1: P₁ P2 F H₂:₁ = 1₂ Ha: ₁ 2

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be:   H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF   H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF   H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF   H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF   H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF   H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is:   left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Test the daim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.01 significance level. The null and alternative hypothesis would be: Ho: HM > Hp Ho:PM > PF Ho:PM PF H1:µM > µp H1:PM + PF H1:µM + µp The test is: right-tailed left-tailed two-tailed Based on a sample of 20 men, 40% owned cats Based on a sample of 60 women, 60% owned cats test statistic = [three decimal accuracy] p-value = [three decimal accuracy] Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level.The null and alternative hypothesis would be:   H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is:   two-tailed right-tailed left-tailed Based on a sample of 300 people, 74% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis