Two genes are on separate chromosomes (i.e., unlinked). One homologous pair of chromosomes carries the 'A' and 'a' alleles, while another homologous pair of chromosomes carries the 'B' and 'b' alleles. Based on what you know about Independent Assortment and probability, what percent of the time will the following occur: 1. 'A' goes with 'B' and 'a' goes with 'b'? 2. 'A' goes with 'b' and 'B' goes with 'a'? Therefore, can we compute a distance of 60 map units for two genes by a two point cross? Yes or No. Why?

In one of his experiments, Mendel crossed homozygous yellow plants with homozygous green plants. The resulting F1 generation was allowed to self-fertilize. The F2 generation produced 930 yellow seeds and 305 green seeds. What are the genotypes of this F2 generation? O YY : yy O Yy : yy O Yy: yy O YY: Yy : yy

Three corn seed traits are C for red, c for white; S for plump, s for shrunken; W for normal, w for waxy. Use the data from the testcross to map the distances and order of these three loci. Show calculations and illustrate the gene map. (Hint: drawing out the chromosomes and gametes will help.)              Parents:         CCssWW (CsW/CsW)          X       ccSSww (cSw/cSw)              Trihybrid:      CcSsWw (CsW/cSw) X       ccssww (csw/csw)   Test cross offspring   Seed trait Gamete from trihybrid Number Red, shrunken, normal CsW 2777 White, plump, waxy cSw 2708 R ed, plump, waxy CSw 116 White, shrunken, normal csW 123 Red, shrunken, waxy Csw 643 White, plump, normal cSW 626 Red, plump, normal CSW 4 White, shrunken, waxy csw 3 Total number of progeny:   7000

Two gene loci, A and B, are on separate chromosomes and alleles A and B are dominant over alleles a and b.    A codes for long branches, a codes for short branches.  B codes for green leaves and b codes for blue leaves.  A branch diagram or a punnett square would be useful for you to work this problem. What percentage of the progeny will have short branches and blue leaves from a cross AaBb × Aabb?  Group of answer choices 1/8 1/4 1/2 3/4

Black coat Brown coat A heterozygous dog with a black coat (C¹C2) is crossed with a heterozygous dog with a yellow coat (C³C2). Determine the phenotypic ratio of offspring produced Yellow coat In a particular breed of dog, the following genotypes and their respective phenotypes are known: Record your 3 digits answer accordingly: • C'C- black coat • C'C²= black coat • C²C²-brown coat • C'C'=yellow coat • C'C²=yellow coat • C'C'=yellow coat

The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…

Which of the following statements are true regarding the F2 offspring of a mapping cross for three genes on the same chromosome?

Calico is a coat color found in cats, which is caused by a SEX-LINKED, CODOMINANT allele, where B = black, O = orange, and BO = calico, The following genotypes are possible; Female cats can be black Xx°, orange XOX°, or calico Xºx°, Male cats can be black XDY or orange XY. An orange male and a black female mate. What proportion of their offsprings will black? O 100% O 50% O 25% O 0%

You are doing a genetics experiment with the fruit fly. In the “P” generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings. All of the flies in the F1 generation are brown and have normal wings. Assume the genes are not found on a sex chromosome. Indicate the body color alleles with B and b and the wing size alleles with N and n. 1) When the flies in (b) and (c) are mated, you count 1600 offspring in the F2 generation. If the body color gene and wing type genes are not linked, how many flies of each phenotype would you expect? (Be sure to use a Punnett square for a dihybrid cross to show your work.)     Show your work: Expected flies if the loci are unlinked: _________: # of brown, winged flies (Genotype: ______________) _________: # of black, winged flies (Genotype: ______________) _________: # of black, wingless flies (Genotype: ______________) _________: # of brown, wingless flies (Genotype:…

In humans, as well as in many other animals and some plants, the sex of the individual is determined by sex chromosomes. The sex chromosomes are one pair of non-homologous chromosomes: XX represents a female, while XY represents a male. When a gene for a specific trait Is attached to the X or Y chromosome, we say it is sex-linked, and when it is attached to the X chromosome, we say it is X-linked. Alleles for these linked traits, such as hemophilia or color blindness, crosses, may be recessive or dominant. This is one possible cross (above) for the X-linked condition known as hemophilia. Which pair of parents is most likely to have a hemophiliac daughter? A) carrier mother and unaffected father B) carrier mother and hemophiliac father hemophiliac mother and a carrier father D) unaffected, non-carrier mother and hemophiliac father