Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
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### Problem Statement:

Two aqueous NaOH streams are combined. Stream A is 26% NaOH by mole. Stream B is 69% NaOH by mole. The product (combined) stream has a flow rate of 125 lbmole/h and is 57% NaOH by mole.

**Objective:** 
Determine the flow rate of stream A and stream B (lbmole/h).

### Explanation:

To solve this problem, you need to set up a material balance equation for the NaOH components and the total flow rate. Follow these steps:

1. **Define Variables:**
   - Let \( F_A \) be the flow rate of Stream A (in lbmole/h).
   - Let \( F_B \) be the flow rate of Stream B (in lbmole/h).

2. **Given Information:**
   - Stream A: 26% NaOH by mole (\( x_A = 0.26 \))
   - Stream B: 69% NaOH by mole (\( x_B = 0.69 \))
   - Combined Stream: 125 lbmole/h, 57% NaOH by mole (\( x_C = 0.57 \))

3. **Total Flow Rate Balance:**
   \[
   F_A + F_B = 125 \ \text{lbmole/h}
   \]

4. **NaOH Component Balance:**
   \[
   0.26 F_A + 0.69 F_B = 0.57 \times 125
   \]

5. **Solving the Equations:**
   From the NaOH balance equation:
   \[
   0.26 F_A + 0.69 F_B = 71.25
   \]

   Using the total flow rate balance:
   \[
   F_A + F_B = 125
   \]

   You can use these two equations to solve for \( F_A \) and \( F_B \).

### Solution:
This section can be used to show the detailed mathematical steps for solving the equations to find \( F_A \) and \( F_B \). 

**Step-by-Step Solution:**

1. Isolate \( F_B \) from the total flow rate balance equation:
   \[
   F_B = 125 - F_A
   \]

2. Substitute \( F_B \) in the NaOH component balance equation:
   \[
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Transcribed Image Text:### Problem Statement: Two aqueous NaOH streams are combined. Stream A is 26% NaOH by mole. Stream B is 69% NaOH by mole. The product (combined) stream has a flow rate of 125 lbmole/h and is 57% NaOH by mole. **Objective:** Determine the flow rate of stream A and stream B (lbmole/h). ### Explanation: To solve this problem, you need to set up a material balance equation for the NaOH components and the total flow rate. Follow these steps: 1. **Define Variables:** - Let \( F_A \) be the flow rate of Stream A (in lbmole/h). - Let \( F_B \) be the flow rate of Stream B (in lbmole/h). 2. **Given Information:** - Stream A: 26% NaOH by mole (\( x_A = 0.26 \)) - Stream B: 69% NaOH by mole (\( x_B = 0.69 \)) - Combined Stream: 125 lbmole/h, 57% NaOH by mole (\( x_C = 0.57 \)) 3. **Total Flow Rate Balance:** \[ F_A + F_B = 125 \ \text{lbmole/h} \] 4. **NaOH Component Balance:** \[ 0.26 F_A + 0.69 F_B = 0.57 \times 125 \] 5. **Solving the Equations:** From the NaOH balance equation: \[ 0.26 F_A + 0.69 F_B = 71.25 \] Using the total flow rate balance: \[ F_A + F_B = 125 \] You can use these two equations to solve for \( F_A \) and \( F_B \). ### Solution: This section can be used to show the detailed mathematical steps for solving the equations to find \( F_A \) and \( F_B \). **Step-by-Step Solution:** 1. Isolate \( F_B \) from the total flow rate balance equation: \[ F_B = 125 - F_A \] 2. Substitute \( F_B \) in the NaOH component balance equation: \[
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