Traverse Surveying Question In a closed loop traverse of 1 km total length, the closing errors in departure and latitude are 0.3 m and 0.4 m respectively. The relative precision this traverse will be
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- Given are the observed data for a traverse obtained from a transit-tape survey. Determine the corrected distances and corrected bearings using compass rule and transit rule. Also, determine the linear error of closure and bearing of the side of error.Given the accompanying tabulation are the observed data for a traverse obtained from a transit-tape survey. Determine the latitudes and departures of each course and balance these quantities by employing the Transit rule. Tabulate values accordingly.A. Compute the total linear misclosure for departure CD.B. Compute for the total linear misclosure for Latitude CL. C. Compute for the correction needed for the latitude of course AB and EAD. Compute for the correction needed for the departure of course AB and EA.E. Compute for the Adjusted length of course AB and EA. F. Compute for the Adjusted bearing of course EA.In a traverse survey, closing errors means O a. the error in the traverse operation O b. the actual distance by which the traverse fails to close O c. the distance between the starting and end point of an open traverse O d. the bearings observed are unaffected by local attraction ?
- Solve the following problems showing your complete solutions. Draw the figure completely labelled with all the notations used in your solution. 1.) Given in the table below is the technical descriptions of a transit-tape survey of a closed traverse. Balance the traverse using transit rule. LINE DISTANCE (m) BEARING 1 –2 56 S 500 15’ E 2 –3 50 S 400 25’ E 3 –4 30 S 600 45’ W 4 –5 43 N 580 20’ W 5 –6 46 N 560 40’ W 6 –1 49 N 440 30’ ELinear Error of Closure Given a closed traverse with sum of south latitudes exceeds the sum of north latitudes by 3.550 m and the sum of east departures exceeds the sum of the west departures by 2.830 m, determine the following: a.) The Linear Error of Closure. b.) The Bearing of Error. c.) The Relative Precision of the measurements made. Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. Please provide a proven and accurate solution. Thank you so muchQ. What is mean by traverse surveying? How does it differ from chain surveying? Distinguish between a closed traverse and open traverse.
- Question In a closed loop traverse of 1 km total length, the closing errors in departure and latitude are 0.3 m and 0.4 m respectively. The relative precision of this traverse will be A 1:2000 B 1:3000 1:4000 D 1:50001. Determine the distance between survey stations R and S, which are separated by a body of water. An EDM device is not available. A baseline RT is established and taped; the angles at the stations have been measured and adjusted. Compute the required distance RS using the given data. S R River 345.67 ft Baseline T 4 R-ST = 67° 11'39" 4 T-RS = 33°49'38"4) For a traverse having a precison ration of 1:7,024 and total distance of 352 what is the total error? Express the error to 3 decimals
- 1. The interior angles X, Y, and Z of a triangular traverse were measured with the same precision. The results were as follows: Station Interior Angles Number of Measurements X 410 3 Y 650 4 Z 750 2A tachometric surveying was performed by a surveyor. The transit used has a stadia interval factor of 90.98 and stadia constant of 0.16m the instrument was set at station O on the line between station C and E. The following stadia readings were takena) Plot the closed traverse based on the observed data.