The simple beam shown, 76.2-cm. long ( = a + L + d ), is made of AISI C1022 steel, as rolled, left a forged. At a =25.4 cm , F1 = 1360.5 kg. is a dead load. At d = 25.4 in , F2 = 1088.4 kg. is repeated, reversed load. For N = 1.5 , indefinite life, and h = 3b , determine b and h . (Ignore stress concentration).

A lightly welded steel beam shown in Figure 5 is continuously supported along its length. A downward concentrated load of 4P acts at Point C, and two downward concentrated loads P act at Points A and E. The beam with full lateral restraint is bent about its major principal x-axis. Determine the followings: a. Section type based on section slenderness; b. Effective section modulus; c. The maximum design value of P. A k B fu 6 m d tw bf 6 m tf 4P d bf tw tf = - = fyf= fyw 6 m D um * 550 mm 206 mm 6 mm 10 mm 320 MPa = 340 MPa Zx=1362985 mm³ Sx 1533750 mm³ Figure 5 Steel beam under design loads. 6 m P E

TASK 3 250 180 14 I 30 24 Weld 450 A compound girder consists of a steel joist with steel plates welded onto each flange as shown. If the ends are simply supported and the effective span is 10 m, what is the maximum UDL which can be supported by the girder? [kN/m] Allowable longitudinal stress in plates = 110 MN/m² Allowable load in shear for each weld = 60 kN/m Allowable shearing stress in web of girder = 75 MN/m² Note: 1.0 MN/m² = 1.0 N/mm² 50

Question # 1: Determine the force in each member of the truss and state if the members are in tension or compression. 300 lb 600 15 B 60015 GOO G 11. 244in. 6 ft load at point B, D, F = 600 lb load at pount A and H=300 lb distance AC = CE =EG = GH = 8FT -80---SA- [Answer: FAB=15001b-C. Fac-12001b-T, Fac0, For-12001b-T, Fan+ 12001b-C, F₁-601b-C. Form 721h-T, Use symmetry to obtain the rest of the members]

please use only set 1 data table thank you this is non graded

Determine the forces in members using the method of section FE, LK, and LG. Include your complete solution along with its free body diagram.

A rectangular tied braced column is reinforced with 6-28mm bars as shown in the figure below. Check the adequacy of the column for the following gravity loads: - - - - - - Service dead load = 1050kN Service live load = 850 kN Service dead load moment = 39 kN-m Service live load moment = 27 kN-m top=bott. = 1.0 40 lu = 5.0m f = 27.6 N/mm², fy = 414 N/mm² axis of bending 500mm Ties 10mm@300c/c } 350mm At eccentricity of 40mm P M +40 + 500mm MU +40- P Top end Bott. end

Figure 1 shows the cross-section of a heavily welded I-section steel column under axial compression. The yield stress of the steel section is 300 MPa. (a) Check the slenderness of the flanges and webs. (b) Determine the effective and gross areas of the cross-section. (c) Determine the design axial capacity of the cross-section. 380 E 10 425 -8 Figure 1. Cross-section of the rectangular hollow section steel column (Units: mm)

AW10x30, 3.1 m long A36 steel is used as a column with fixed ends to support a service dead load of 267 kN. Calculate the maximum service live load the column can sustan uning LRFD Use theoretical value of k. Write your answer rounded to the nearest whole number in KN Use properties Ag = 5.703 mm2, rx = 111.25 mm,  ry = 34.8 mm.   Use stored value. Asnwer in 5 decimal places.

It is not graded question and it is complete question.Plz, solve it for your understanding.Structural Analysis-2Plz, write as this process: Given Data Required solution Results Attempt Neat and Clean with proper diagrams