ANALYSISANALYSIS:A DNA strand undergoes all the process included in the central dogma. The DNA strand used as a template isgiven below:Parent strand DNA:DNA daughter strand:5-AGA-ACT-AAA-CТА-ТСG-СTT-CGT-3'hnRNA:MRNA:original protein:mutated mRNA:mutated protein:second letterAGUUUPheUCU)UCCUAUUGUCysUUCUUUAUAC TyrUGCSerUAA stop UGA stop| AUAG stop UGG TrpUCALeuUUGUCGGCUUCCUCAUCGUHisCACСААCUCCCCGCLeuProArgACUAССАCGCGAGlnCAG SOAAUCUGCGGAUUACUAGUAGC SerAAsnAUC lleAAUAACCAACThrAAAAAG LysGAUАСАAUG Met ACGAGG ArgGUUGCUGGUUAspGUCGGCGCCGCAGCGGACValGUAAlaGlyAGAG GluGGGGAAGGAGUGGTranslating the unmutated MRNA that was obtained after splicing, the original protein sequence will be?The original protein is [A](For your answer, use the one-letter symbol (all caps) for the amino acid residues separated by dashes, e.g. C-A-S-H).first letterthird letter

Answered: Image /qna-images/answer/14e64cbb-6ff8-4897-86fa-9eaeae3e34cf.jpg

Answered: Translating the unmutated MRNA that was…

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter13: An Introduction To Genetic Technology

Section: Chapter Questions

Problem 15QP

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AUG Met ACG ANALYSIS ANALYSIS: A DNA strand undergoes all the process included in the central dogma. The DNA strand used as a template is given below: Parent strand DNA: 5-AGA-ACT-AAA-СТА-ТCG-СТT-CGT-3 DNA daughter strand: hnRNA: MRNA: original protein: mutated MRNA: mutated protein: second letter G UCU UUU Phe UAU Tyr UGU UGC Cys UAA stop UGA stop| A UAG stop UGG Trp UUC UCC UAC Ser Leu UCA UUG UUA UCG G CUU CCU CAU CGU His CAC CAA CUC C CGC Leu CUA Pro Arg A ССА CGA Gln CAG CUG CCG CGG AUU ACU AAU AUC lle A AUA AAC Asn AAA AGC AGA AGU Ser ACC Thr АСА AAG LyS GAU ASP AUG Met ACG AGG Arg G GUU GCU GGU) GUC GCC GAC GGC Val GUA GCA Ala GAA Gly GGA A Glu GUG GCG GAG GGG G Translating the unmutated MRNA that was obtained after splicing, the original protein sequence will be? The original protein is [A] (For your answer, use the one-letter symbol (all caps) for the amino acid residues separated by dashes, e.g. C-A-S-H). first letter third letter
ENE 2: Nose Style DNA Template Strand ATG- GGG- CTT- CTC- TTT MRNA tRNA Amino Acids APPEARANCE
Select the characteristics/descriptions of DNA polymerase. Select ALL that apply requires a primer adds nucleotides to 3' end of DNA strand adds nucleotides to 5' end of DNA strand does not require primer has 3'-to-5' exonuclease activity that allows "proofreading" of DNA strand being made
BONUS: Why can't RNA viruses use cellular RNA Polymerase to copy their genetic information? Because cellular RNA Polymerases are O RNA Dependent RNA Polymerase O RNA Dependent DNA Polymerase O DNA Dependent RNA Polymerase O DNA Dependent DNA Polymerase prt s home
Mutated DNA Template Strand #1: 3’-T A C T G T C T G A C G A T C-5’ Complementary DNA sequence: mRNA sequence transcribed from template:
Directions: 1. Use the DNA code to make a replicated copy of DNA. 2. Use the replicated DNA code to create your transcription mRNA code. 3. Use the mRNA code to create your tRNA anticodon. 4. USE THE MRNA CODE TO DETERMINE YOUR AMINO ACIDS. MAKE SURE TO PUT YOUR LETTERS IN ALL CAPS! DNA ATG GCA AGC GCT TGA DNA TAC REPLICATION DNA TO MRNA AUG TRANSCRIPTION MRNA to tRNA UAC ANTICODON MRNA to AMINO AUG (START) (STOP) ACID TRANSLATION DNA ATG ССА GAC ACG TGA DNA ТАС REPLICATION DNA TO MRNA AUG TRANSCRIPTION MRNA to TRNA UAC ANTICODON MRNA to AMINO AUG (START) (STOP) ACID TRANSLATION
Match the DNA repair mechanism to the type of repair it fixes. Base excision repair DNA polymerase proofreading Non-homolgous end-joining Mismatch repair Nucleotide excision repair Double strand breaks Mismatches in S-phase Mismatches after S-phase, before M-phase Mismatches in interphase Thymidine Dimer Double strand breaks Mismatches in S-phase Mismatches after S-phase, before…
DNA strand below: 3’ T A C A T G C C G A A T G C C 5’ Discuss how will replication happen by mentioning the enzyme needed then transcribe to form mRNA. Discuss what will happen to mRNA, then translate, mentioning the anticodon to be used. Look at the genetic code to know what amino acid will become part of the polypeptide chain. 1. Give the discussion of the entire procedure
A. Create the complimentary strand for the DNA strand below. Make sure to label the parts and direction of the strand. 5’-AACGGTCCAGTCCAAGTTACG-3’ 2. Below is a segment of DNA that is ready to be replicated. Outline the processes that the segment will go through during replication. Make sure to include the names of the enzymes that are involved. AATTGCCTGCTAGTCTCAG TTAACGGACGATCAGAGTC B. DNA: G T A C G C G T A T A C C G A C A T T C RNA: C A U G C G CAU A U G G C U G U A G Codons: AUG - CGC - AUA -UGG - CUG - UAA Anti-codons: UAC - GCG -UAU - ACC - GAC - AUU Amino acids: Met- Arg - Ile - Try - Leu Using the example above transcribe the following DNA strands into m-RNA and translate that strand into a polypeptide chain identifying the codons, anti-codons and amino acid sequence. 3. DNA: A T A C G A A A T C G C G A T C G C G G C G A T T C G G 4. DNA: T T T A C G G C C A T C A G G C A A T…
BONUS: Why do RNA viruses such as the COVID coronavirus, influenza virus and HIV have much higher mutation rates than DNA viruses such as Herpes viruses? O DNA polymerases which copy viral RNA have much higher mutation rates than RNA polymerases which copy viral DNA O RNA polymerases which copy viral RNA have much higher mutation rates than DNA polymerases which copy viral DNA RNA viral 60S ribosomes make many ore mutations than DNA viral 40S ribosomes O RNA viral gyrases make more mistakes than DNA viral helicases
40 Shown below is the antisense strand of DNA. What is the amino acid sequence that corresponds to this code? 5' AAAGCATACCGG 3' Second letter G. UUU Phe UCU UAU) Tyr UGC Cys UGU UUC UCC UAC Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUA UCA UUG Leu UG CAU His CGU CGC CGA CGG CU CUU CUC CUA CUG CAC Pro Leu Arg CCA CAA) Gin CCG CAG AAU AUU AUC lle AUA AUG Met ACG ACU AGU AAC Asn AGC Ser ACC ACA Thr AAA1 AGA AAG Lys AGG Arg GAU) Asp GGC GAC Ala GAA GGU GUU GUC GUA Val GCU GCC Gly GCA GGA Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a PRO-VAL-SER-PHE PHE-ARG-MET-ALA GLY-HIS THR-LYS d LYS-ALA-TYR-ARG First letter Third letter
Fill in the blank spaces below with the most appropriate terms. The word bank is not provided. DNA replication in bacterium Escherichia coli begins at a site in the DNA called At the replication fork, the strand is synthesized continuously while the strand is synthesized discontinuously (in fragments). The new DNA strand, which is synthesized discontinuously, initially consists of short DNA pieces that are called A short RNA primer at the beginning of each of the DNA fragments is synthesized by an enzyme called and this RNA primer is later removed by the enzyme called using its activity. Single-strand breaks (nicks) that are left behind in this process are sealed by the enzyme called A Moving to another question w!l save this resporse Quebon 4 In

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