Transcribe an mRNA sequence from this TEMPLATE STRAND of DNA 3' CGTACGTGTATCCCATCC 5' 5' GCAUGCACAUAGGGUAGG 3' 5' GCAUGCACAUAGGGUAGG 3' 3' CGUACGUGUAUCCCAUCC 5' 5' GCATGCACATAGGGTAGG 3' 3' CGTACGUGTATCCCATCC 5'

Transcribe an mRNA sequence from this TEMPLATE STRAND of DNA 3' CGTACGTGTATCCCATCC 5' 5' GCAUGCACAUAGGGUAGG 3' 5' GCAUGCACAUAGGGUAGG 3' 3' CGUACGUGUAUCCCAUCC 5' 5' GCATGCACATAGGGTAGG 3' 3' CGTACGUGTATCCCATCC 5'

Name: Transcribe an mRNA sequence from this TEMPLATE STRAND of DNA3' CGTACGT
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Description: Transcribe an mRNA sequence from this TEMPLATE STRAND of DNA3' CGTACGTGTATCCCATCC 5'5' GCAUGCACAUAGGGUAGG 3' 5' GCAUGCACAUAGGGUAGG 3'3' CGUACGUGUAUCCCAUCC 5'5' GCATGCACATAGGGTAGG 3'3' CGTACGUGTATCCCATCC 5'

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter30: Protein Synthesis

Section: Chapter Questions

Problem 1P

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The template strand of a gene has the sequence 5'-ATGCCTAGCCTAGGACT-3'. What will the sequence of the transcript from this gene be? 5' AGUCCUAGGCUAGGCAU 3 5 ATGCCTAGCCTAGGACT 3' 5 AUGCCUAGCCUAGGACU 3' 5' MAUGCCUAGCCUAGGACUAAAAAAAAAA 3" 5' AGTCCTAGGCTAGGCAT 3" V.
What is the DNA template for the RNA sequence 5' UAACGGAGCCUAAUC 3'? O 5' GAUUAGGCUCCGUUA 3' O 5' AUUGCCUCGGAUUAG 3' 5' GATTAGGCTCCGTTA 3' 5' TAACGGAGCCTAATC 3' O 5'ATTGCCTCGGATTAG 3'
Telomerase supplies its own template RNA molecule as shown in Figure 3 below: B AAUCCCAAU TTAGGGTTAGGGTTAGGGTTAGGGTTAGGGTTAGGG-W' JAATCCCAATCCCAATCCCAA-X' Figure 3 (i) Label the ends (5' and 3') on the DNA and RNA strand at position X, Y and Z, in the Figure 3. (ii) Draw and explain the two loop structures at the end of telomere.
Give the RNA molecule sequence transcribed from the following DNA sequence of a eukaryotic gene and with the correct 5' and 3' ends. DNA: 5'-ATAGGGCATGT-3' 3'-TATCCCGTACA-5' <--- template strand Group of answer choices 5'-ATAGGGCATGT-3' 3'-UAUCCCGUACA-5' 5'-AUAGGGCAUGU-3' 3'-TATCCCGTACA-5'
For this double stranded DNA: 3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’ 5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’ , while using the bottom strand is the template for transcription. If the START CODON is AUG and the STOP CODON IS UGA, how many amino acids are in the encoded protein and what is the primary structure?
Consider the following DNA template: 5’-AAGAGGTTCCAATGCAGGCACTCACCAACTCTTAAATAAA-3’ 3’-TTCTCCAAGGTTACGTCCGTGAGTGGTTGAGAATTTATTT-5’ If the bottom DNA strand is used as template to transcribe mRNA, predict the amino acid sequence that would result from the process of translation. Met-Ala-Leu-Thr-Gln-Glu-Gly Met-Gly-Ser-Leu-Asn-Ser-Gln Met-Thr-Asn-Ser-Leu-Ala-Gln Met-Gln-Ala-Leu-Thr-Asn-Ser Met-Glu-Ala-His-Trp-Ser-Tyr
This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' (i) Draw the structure of hairpin loop that will be formed during the end of transcription. (ii) Describe the function of the hairpin loop during transcription.
Given Sequence: 3’-TACGGTCCGGATTCGGTAGCTAGCATC-5’ Provide: Complementary Strand: Transcript Amino Acid Sequence 2.Given Sequence: 5’-GGGCATATGCCGTTTACCGGTTTGACTAAATAACCA-3’ Provide: Complementary Strand: Transcript Amino Acid Sequence 3.Given Sequence: 3’-AAC CAA TAC GTG AGG ATA CCA AGT AAC ACT CCC-5’ Provide: Complementary Strand: Direct Transcript: Transcript for Translation: Amino Acid Sequence:
What is the sequence of the mRNA transcript that will be produced from the following sequence of DNA? The top strand is the template strand, the bottom strand is the coding strand. 5’ – TCGGGATTAGACGCACGTTGGCATACCTCG – 3’ 3’ – AGCCCTAATCTGCGTGCAACCGTATGGAGC – 5’ Enter the mRNA sequence here (pay close attention to the direction of the molecule!): 5'-_____-3'
This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.
b) Shown below is a short gene of an unknown bacteria genome (Figure 2). (Note: Transcription starts at Transcription Start Site (TSS).) 5'TATTATAACGCATGACGAGCCATGCATTATCGGTATATGCACTGACCCGGAAAGGCTCCTTTTGGAGCCTTTTTT-3' 3'-ATAATATTGCGTACTGCTCGGTACGTAATAGCCATATACGTGACTGGGCCTTTTCCGAGGAAAACCTCGGAAAAA-5' Promoter (i) (ii) TSS (iii) Terminator Figure 2 Which DNA strand (the top or the bottom) is used by polymerase as a DNA template? List the mechanistic steps that can trigger the initiation of transcription by the Sigma Factor. What are the amino acids translated from the resulting mRNA? Indicate the amino (NH₂*) and carboxyl (COO) termini of the polypeptide chain.
5' AGGGUUUGGGAUGAAUCGACGACGAUCCUACGUACUAAGUA 3' Write the amino acid sequence for this portion of the coding sequence: Write the double-stranded DNA sequence that corresponds to the MRNA above. Label 5' and 3' ends. Would transcription have occurred using the top or bottom strand as the template? Imagine you discover a mutation in the DNA, within the coding sequence of the corresponding mRNA above. You determine that the mutation does not result in a change to amino acid sequence. What is the most likely reason for this?