To test whether the variances are equal, the p-value is calculated as p=0.008 based on the test statistics. What is the correct conclusion? Reject null (H0) hypothesis with α = 0.0005 Reject null (H0) hypothesis with α = 0.001 Reject null (H0) hypothesis with α = 0.005 Reject null (H0) hypothesis with α = 0.01

The breaking strengths of cables produced by a certain company are approximately normally distributed. The company announced that the mean breaking strength is 2140 pounds with a variance of 32,761. A consumer protection agency claims that the actual variance is higher. Suppose that the consumer agency wants to carry out a hypothesis test to see if its claim can be supported. State the null hypothesis Ho and the alternative hypothesis H₁ they would use for this test. Ho: H₁: 0 μ OSO 0=0 X X Р ☐#0 S O0 020

A random sample of 23 bags of apples (marked as 10 pounds each) received by a large grocery chain tested out as having a mean of 9.2 pounds with a variance of 2.56 pounds. Test whether the true mean of all bags is under 10 pounds. Set up hypotheses. Perform the appropriate test by showing your formula. Interpret the results using a Type I (alpha) error of .05. Also provide the p value here. Also construct a 95% confidence interval around your sample mean (X bar) that should contain the true mean (mu). Also interpret this interval.

To evaluate the effect of a treatment, a sample of n = 8 is obtained from a population with a mean of μ = 40, and the treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be M = 35. (Use the 4-step procedure to conduct the hypothesis test)  If the sample variance is s2 = 32, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with α = .05? If the sample variance is s2 = 72, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with α = .05? Comparing your answer for parts a and b, how does the variability of the scores in the sample influence the outcome of a hypothesis test?

A sample of n=18n=18 data values randomly collected from a normally distributed population has variance s2=24.6s2=24.6. We wish to test the null hypothesis H0:σ2=64H0:σ2=64 against the alternative hypothesis H1:σ2<64H1:σ2<64 at a significance of α=0.01α=0.01. What is the value of the test statistic? Write your answer rounded to 3 decimal places. What is the critical value? Write your answer rounded to 3 decimal places.

From 2012-2017 the 5 year remission rate of Breast cancer was 91%. Suppose we wish to know if that percentage has changed in 2020. We take a random sample of 360 breast cancer survivors from 2015-2020 and find out that 315 have remained in remission since. Use a significance level of α = .05.  (a) State the null and alternate hypothesis (b) Can we continue with testing the hypothesis? Why or why not? (c) If possible, proceed with the hypothesis test and reach a conclusion.

Test the claim about the population variance o² at the level of significance α. Assume the population is normally distributed. Claim: o² ≥8.5; α = 0.10 2 Sample statistics: s² = 7.78, n = 25 Write the null and alternative hypotheses. Ho: 0² ≥ 8.5 Ha: 0² < 8.5 (Type integers or decimals. Do not round.) Calculate the standardized test statistic. x² = 21.97 (Round to two decimal places as needed.) Determine the P-value. P-value = (Round to three decimal places as needed.)

For the general population, the average fatigue level is μ = 50. A researcher is testing the hypothesis that engaging a meditation exercise reduces employee fatigue. A sample of n = 30 participants is obtained, and each participant engaged in a meditation exercise for 20 minutes at work each workday for a month. This sample’s average fatigue level was M = 46 with a sample variance of 100 after the month. Please write out the four steps for this hypothesis test assuming an alpha level of .05. Step 1: State your hypotheses Step 2: Find your critical regions in a distribution Step 3: Data Analysis Step 4: Making a decision