What are the two degrees of freedom of the ANOVA? df1=      df2= Use FF-distribution to find the pp-value of the given test-statistic. p= Which of the following describes how the FF-test statistic is computed?    A.  It is the the ratio of the variation among samples over the variation within samples. B.  It is the the sum of the variation among samples and the variation within samples.

A therapist would like to evaluate an intervention for treating depression.  A sample of n = 20 depressed clients is obtained, and each person’s level of depression is measured using a standardized questionnaire before they begin the therapy program.  Two weeks after therapy, each client’s level of depression is measured again.  The average level of depression dropped by 4.0 points following therapy.  The difference scores had a variance of 64.  Identify and Cclculate the appropriate test statistic.Make sure to report the degrees of freedom for the statistical test (if appropriate).  You must show your work to receive full credit. State your conclusions (use a two-tailed test with a = .05 for all tests). Compute an effect size.

When creating a two sided CI for the difference of two means, assuming that the variance of the two populations - from which the samples are obtained - are equal will (keeping everything else constant) make no difference create a wider CI create a narrower CI O increase the significance level

Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on organisms, an expert claimed that the amount of gamma radiation needed to sterilize a colony of tardigrades no longer has a mean of 1150 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy.) A random sample of 25 tardigrade colonies found that the amount of gamma radiation needed to sterilize a colony had a sample mean of 1133 Gy, with a sample standard deviation of 02 Gy. Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is appraximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level af significance, to support that H, the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is not equal to 1150 Cy. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for…

The data in table is from a randomized block design represent blood pressure measurements from an experiment involving 4 age groups, each with 3 persons. The 3 persons within each age group were randomly assigned to drugs, A, B and C with one person per drug. This was done to keep the drug assignments balanced within age groups. Comparing the three drugs in manner that provides balance for or control for possible age effects. Consider the data given in table below and compute; a. Mean Square Due to Treatments (MSTR) b. Mean Square Due to Blocks (MSBL) Mean Square Due to Error (MSE) C. d. F-test Treatments Age Groups (Blocks) A B 1 70 72 2 76 84 3 82 86 4 90 92 Total 318 334 C Total Blocks 80 222 82 242 84 252 88 270 334 986

A sample of n = 16 individuals participates in a repeated-measures study that produces a sample mean difference of 9  with SSD = 960.  Calculate the variance for the sample of difference scores. Calculate the estimated standard error for the sample mean difference.

You have been asked to determine if two different production processes have different mean numbers of units produced per hour. Process 1 has a mean defined as μ₁ and process 2 has a mean defined as µ₂. The null and alternative hypotheses are H₂: μ₁ −μ₂ ≤0 and H₁ : µ₁ − µ₂ > 0. The process variances are unknown but assumed to be equal. Using random samples of 36 observations from process 1 and 49 observations from process 2, the sample means are 60 and 50 for populations 1 and 2 respectively. Complete parts a through d below. Click the icon to view a table of critical values for the Student's t-distribution. THIV IVVI VIMUVUV IVA Since the test statistic is IV The test statistic is t = MITM IV ܝ The critical value(s) is(are) 1.663. (Round to three decimal places as needed. Use a comma to separate answers as needed.) greater than t + ny – 2,0 ² reject Ho. c. Can you reject the null hypothesis, using a probability of Type I error x = 0.05, if the sample standard deviation from process 1…

A sample of 9 days over the past six months showed that that Philip Sherman, DDS, treated the following numbers of patients: 22, 25, 20, 18, 15, 22, 24, 19, and 26. If the number of patients seen per day is normally distributed, would an analysis of these sample data reject the hypothesis that the variance in the number of patients seen per day is equal to 10? Use a = 0.10 level of significance. Use Table 3 from Appendix B. State the hypotheses. Ho: 0² = H₂: 0² 10 Calculate the variance and test statistic. (to 2 decimals) variance = test statistic = What is your conclusion? 10 Do not reject the null hypothesis ✓

Over the years, a sushi restaurant has had a mean customer satisfaction rating of 72.5 with a variance of 24.7. The owner has hired you to perform a hypothesis test to see if using a new menu will have any effect on the variance, o“. To do so, you survey a random sample of 19 customers who ordered from the new menu. For the customers surveyed, the variance of ratings is 44.3. Under the assumption that the customer ratings using the new menu follow a normal distribution, you will perform a chi-square test. Find x, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places.

An electronic company's records show that the mean number of circuit.boards rejected per batch is 5.7 with a variance of 1.4. Due to a change in the molding process, factory management has hired you to perform a hypothesis test to check if the variance, o, has increased. To do so, you test a random sample of 10 batches produced using the new process; the number of circuit boards rejected per batch has a sample variance of 2.5. Under the assumption that the number of circuit boards rejected per batch using the new process follows a normal distribution, you will perform a chi-square test. Find x, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places. * = 0