To change the power factor of an electrical load from unity to 0.9 lag, a capacitor should be connected in parallel to it. Select one: O True O False
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- Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your answers in both rectangular and polar form. (a) i(t)=5002cos(t30) (b) i(t)=4sin(t+30) (c) i(t)=5cos(t15)+42sin(t+30)An industrial load consisting of a bank of induction motors consumes 50 kW at a power factor of 0.8 lagging from a 220-V,60-Hz, single-phase source. By placing a bank of capacitors in parallel with the load, the resultant power factor is to be raised to 0.95 lagging. Find the net capacitance of the capacitor bank in F that is required.The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax
- QUESTION 3 An inductor, a capacitor, and a resistor are connected in parallel with a function generator. The inductor draws 100mA RMS, the capacitor draws 150mA RMS, and the resistor draws 200mA RMS. Find the magnitude of the total current. O 450mA RMS O 544mA RMS O 352mA RMS O 206mA RMSQUESTION 3 An inductor, a capacitor, and a resistor are connected in series with a function generator. The inductor drops 5V RMS, the capacitor drops 20V RMS, and the resistor drops 2V RMS. Find the magnitude of the total voltage. O 27V RMS O 15V RMS O 38V RMS O 9V RMSClear my choice A capacitor is connected in parallel with a load of S= 6000 VA, and pf3D0.8 lag. The load is operating at 180 V and a frequency of 60 Hz. Calculate the capacitance value that will correct the power factor to pf=1. Select one: O a. 0.295 mf O b. None of them c. 0.354 mf O d. 6000 mf An 8 kVA motor operates at a 0.75 power factor, the real power is then: Select one: О 60 KW O 600 W O None of the Answers O 6000 W What term describes the maximum expected error associated with a measurement or a seńsor? 113 ) A ENG 12-A
- An electrical circuit with a sinusoidal current source, a resistor, and a capacitor all connected in parallel. The voltage across the capacitor: Select one: O a. Lags the current of the capacitor by 180° O b. Is in phase with the current of the current source Ос. O c. Lags the current of the capacitor by 90° O d. Leads the current of the current source by 90° O e. Leads the current of the capacitor by exactly 90°An rms voltage of 22.2 V with a frequencyof 1.00 kHz is applied to a 0.290-mH inductor. (a) What is the rmscurrent in this circuit? (b) By what factor does the current changeif the frequency of the voltage is doubled? (c) Calculate the current for a frequency of 2.00 kHzA 68.0-mH inductor and a 5.90-uF capacitor are connected in series with a generator whose frequency is 407 Hz. The rms voltage across the capacitor is 2.00 V. Determine the rms voltage across the inductor. Vo sin 2z ft Ims
- A capacitor is connected in parallel with a load of S= 6000 VA, and pf-0.8 lag. The load is operating at 180 V and a frequency of 60 Hz. Calculate the capacitance value that will correct the power factor to pf%3D1. Select one: O a. None of them O b.0.47 mf O c.0.295 mf O d. 0.354 mfThe 60 Hz AC source and 240 V rms voltage provides a power of 5000 VA for a load with a lagging power factor of 0.85. Determine the reactive power in the capacitor and the value of the capacitor that must be connected in parallel with the load to bring the power factor to 0.92 inductive58. Two capacitors, a 20 µF and a 30 µF, are connected in series to a 60-Hz source. What is the total capacitive reactance? a. 117.96 N b. 221.04 N c. 253.05 N d. 333.16 N