A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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- Answer for this questions A, B, C , D, E, Detailedarrow_forwardThe National Institute of Standard and Technology provided exact data on conductivity properties of materials. Following are conductivity measurements for 11 randomly selected pieces of a particular type of glass. Click this button to reveal the data Conductivtity 1.11 1.07 1.11 1.07 1.12 1.08 0.98 0.98 1.02 0.95 0.95 Download CSV file Download the .csv file or copy/paste the data into Excel. After downloading .csv file, you may want to save it as a Excel Workbook. Based on these data, is there evidence that the median conductivity of this type of glass is greater than 1? Use a 10% level of significance level. a. How many samples of data are there in this study? b. What test you would use for this problem? Select an answer c. The null hypothesis of this test states that Select an answer d. What type of test is this? O One-side Two-sidearrow_forwardValues of modulus of elasticity (MOE, the ratio of stress, i.e., force per unit area, to strain, i.e., deformation per unit length, in GPa) and flexural strength (a measure of the ability to resist failure in bending, in MPa) were determined for a sample of concrete beams of a certain type, resulting in the following data: МОЕ 29.9 33.3 33.6 35.4 35.6 36.0 36.3 36.4 37.6 37.6 Strength 6.0 7.1 7.4 6.2 8.2 6.9 6.9 7.7 6.7 6.6 МОЕ 38.8 38.9 39.7 40.9 42.7 42.7 43.4 45.5 46.1 47.0 Strength 6.9 6.4 7.8 9.1 8.3 8.8 7.7 9.8 7.3 7.6 МОЕ 48.1 49.2 51.8 62.5 69.9 79.6 80.1 Strength 9.8 7.7 7.6 11.5 11.2 11.7 10.8 Fitting the simple linear regression model to the n = 27 observations on x = modulus of elasticity and y = flexural strength given in the data above resulted in ŷ = 7.595, s; = 0.186 when x = 40 and ŷ = 9.706, = 0.263 %3D for x = 60. The simple linear regression model also resulted in a value of s = 0.9008. (a) Explain why s; is larger when x = 60 than when x = 40. The farther x is from…arrow_forward
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- A manufacturer of high-resolution video terminals must control the tension on the mesh of fine wires that lies behind the surface of the viewing screen. Too much tension will tear the mesh, and too little will allow wrinkles. The tension is measured by an electrical device with output readings in millivolts (mV). Some variation is inherent in the production process. Here are the tension readings from a random sample of 20 screens from a single day’s production: 269.5 297.0 269.6 283.3 304.8 280.4 233.5 257.4 317.5 327.4 264.7 307.7 310.0 343.3 328.1 342.6 338.8 340.1 374.6 336.1 From this data, we compute ? = 306.32, ? = 36.21 Compute a 90% confidence interval for the mean tension μ of all the screens produced on this day.arrow_forwardA. Determine the test statistic B. Find the p-valuearrow_forwardOnly answer the questions typed: A. indicate whether it's one or two sidedB. Indicate whether it's a test of means or proportionsC. Write out the expression for determining the P-valuearrow_forward
- Values of modulus of elasticity (MOE, the ratio of stress, i.e., force per unit area, to strain, i.e., deformation per unit length, in GPa) and flexural strength (a measure of the ability to resist failure in bending, in MPa) were determined for a sample of concrete beams of a certain type, resulting in the following data: MOE 29.7 33.1 33.6 35.2 35.4 36.2 36.2 36.3 37.4 37.8 Strength 5.8 7.1 7.2 6.2 8.0 6.9 7.1 7.7 6.7 6.4 МОЕ 38.6 38.7 39.7 40.9 42.7 42.7 43.6 45.7 45.9 46.8 Strength 7.1 6.4 8.0 8.9 8.3 8.8 7.9 9.6 7.3 7.6 МОЕ 47.9 49.2 51.6 62.7 69.7 79.6 80.1 Strength 9.8 7.7 7.8 11.5 11.4 11.9 10.6 Fitting the simple linear regression model to the n = 27 observations on x = modulus of elasticity and y = flexural strength given in the data above resulted in ý = 7.589, s, = 0.180 when x = 40 and ý = 9.749, s, = 0.255 for x = 60. The simple linear regression model also resulted in a value of s = 0.8718. (a) Explain why s, is larger when x = 60 than when x = 40. O The closer x is to…arrow_forwardIn the 2015 AFC Championship game, there was a charge that the New England Patriots underinflated their footballs for an advantage. The Patriots' opponents during the championship game were the Indianapolis Colts. Measurements of the Colts' footballs were taken. The balls should be inflated to between 12.5 and 13.5 pounds per square inch (psi). The accompanying data consists of six of the eight measurements on the Colts' footballs. Complete parts (a) and (b) below. 12.75, 12.50, 12.15, 12.35, 12.55, 12.30 The test statistic is = (Round to two decimal places as needed.) The p-value is = (Round to three decimal places as needed.) b. Use the data to construct a 95% confidence interval for the mean psi for the Colts' footballs. How does this confidence interval support your conclusion in part (a)? The 95% confidence interval is ___ psi to ___ psi. (Round to two decimal places as needed. Use ascending order.)arrow_forwardhe General Social Survey asked the question, "After an average work day, about how many hours do you have to relax or pursue activities that you enjoy?" to a random sample of 1,155 Americans. The average relaxing time was found to be 1.65 hours. G. What is D. What is the statistic given? Describe it in words and give the numerical value. E. Describe the parameter corresponding to the statistic from Part (D) in words.arrow_forward
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ISBN:9780134753119
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