Titration Experiment 1: Acid-Base Titration: Unknown HCl Write chemical equation + H2C NaCHcay"+ Noclag) HClcog> Nacog tOH cop) + H Ceg) + Cl →Na ta) + Clan+ Write NIE Enter the data into the table and choose three titrations to find the molarity of the unknown He Unknown # HCI Titration 1 Titration 2 Titration 3 Titration 4 Titration 5

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Titration Experiment 1: Acid-Base Titration: Unknown HCl
Write chemical equation
*+ HClcags N s
→ Naclceg) + H,O
Write NIE
OH c) + HEogs → H2OC)
Enter the data into the table and choose three titrations to find the molarity of the unknown HCI.
Unknown # HCI
Titration 1 Titration 2 Titration 3 Titration 4 Titration 5
Volume NaOH used to titrate
unknown HCI solution
17.43ml 16.5O ml662 mll16.57ml16.6dmL
Molarity of NaOH used for
each titration
0.2564
0.1787/01692/0.1704/oiado1703
Molarity of HCI
Average M HCI (avg ±
standard deviation)
10.1717
1.63
% Precision
Calculations
1. Provide one representative calculation that you used to determine the molarity of HCI. Be
sure to show all units and use proper sig figs!
V HCI-25mL
MHCI =?
VN2OH = 16.6lmL
MNAOH=0.2564
MHCI VHCI=MNAOH VAa OH
MHCI 25=O. 1564 16.61
MHCI= 0.2564.16.61
25
MHCI=0.1703
2. Average molarity of three titrations.
6.1787+0.1692+0.1704+0.1619+ O.1703
MACI= 0.117
Transcribed Image Text:Titration Experiment 1: Acid-Base Titration: Unknown HCl Write chemical equation *+ HClcags N s → Naclceg) + H,O Write NIE OH c) + HEogs → H2OC) Enter the data into the table and choose three titrations to find the molarity of the unknown HCI. Unknown # HCI Titration 1 Titration 2 Titration 3 Titration 4 Titration 5 Volume NaOH used to titrate unknown HCI solution 17.43ml 16.5O ml662 mll16.57ml16.6dmL Molarity of NaOH used for each titration 0.2564 0.1787/01692/0.1704/oiado1703 Molarity of HCI Average M HCI (avg ± standard deviation) 10.1717 1.63 % Precision Calculations 1. Provide one representative calculation that you used to determine the molarity of HCI. Be sure to show all units and use proper sig figs! V HCI-25mL MHCI =? VN2OH = 16.6lmL MNAOH=0.2564 MHCI VHCI=MNAOH VAa OH MHCI 25=O. 1564 16.61 MHCI= 0.2564.16.61 25 MHCI=0.1703 2. Average molarity of three titrations. 6.1787+0.1692+0.1704+0.1619+ O.1703 MACI= 0.117
3. Standard deviation across three titrations (put your data in Excel. Write your stdev formula
below)
4. Percent Precision for three titrations
Transcribed Image Text:3. Standard deviation across three titrations (put your data in Excel. Write your stdev formula below) 4. Percent Precision for three titrations
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