A 0.298 g sample of an unknown monoprotic acid is titrated with 0.300 M KOH to the equivalence point. It requires 15.8 mL of KOH to reach this point. Elemental analysis is also performed, showing that the acid contains 1.6% H, 22.2% N, and 76.2% O. Use this information to determine the molecular formula and the molar mass of the unknown acid. molecular formula of unknown acid: HNO molar mass of unknown acid: Draw the Lewis structure of the unknown acid in which the H atom(s) are bonded to O atom(s). g/mol

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A 0.298 g sample of an unknown monoprotic acid is titrated with 0.300 M KOH to the equivalence point. It requires
15.8 mL of KOH to reach this point. Elemental analysis is also performed, showing that the acid contains 1.6% H, 22.2% N, and
76.2% O. Use this information to determine the molecular formula and the molar mass of the unknown acid.
molecular formula of unknown acid: HNO
molar mass of unknown acid:
Draw the Lewis structure of the unknown acid in which the H atom(s) are bonded to O atom(s).
Select
3
Draw
N H O
Templates
More
Erase
Q2 Q
g/mol
Transcribed Image Text:A 0.298 g sample of an unknown monoprotic acid is titrated with 0.300 M KOH to the equivalence point. It requires 15.8 mL of KOH to reach this point. Elemental analysis is also performed, showing that the acid contains 1.6% H, 22.2% N, and 76.2% O. Use this information to determine the molecular formula and the molar mass of the unknown acid. molecular formula of unknown acid: HNO molar mass of unknown acid: Draw the Lewis structure of the unknown acid in which the H atom(s) are bonded to O atom(s). Select 3 Draw N H O Templates More Erase Q2 Q g/mol
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