J. J. Thomson is best known for his discoveries about thenature of cathode rays. His other important contributionwas the invention, together with one of his students, ofthe mass spectrometer, a device that measures the ratioof mass m to (positive) charge q of an ion.The spectrometer consists of two regions as shown inthe figure.(Figure 1) In the first region an electric fieldaccelerates the ion and in the second the ion follows acircular arc in a magnetic field. The radius of curvature ofthe arc can be measured and then the m/q ratio can befound.Part AAfter being accelerated to a speed of 1.00x105 m/s, the particle enters a uniformmagnetic field of strength 0.900 T and travels in a circle of radius 33.0 cm(determined by observing where it hits the screen as shown in the figure). Theresults of this experiment allow one to find m/q.Find the ratio m/q for this particle.Express your answer numerically in kilograms per coulomb.► View Available Hint(s)m/q=SubmitV ΑΣΦPrevious AnswersReview | Constants=kg/C

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Thomson is best known for his discoveries about the re of cathode rays. His other important contribution the invention, together with one of his students, of nass spectrometer, a device that measures the ratio ass m to (positive) charge q of an ion. spectrometer consists of two regions as shown in gure.(Figure 1) In the first region an electric field lerates the ion and in the second the ion follows a lar arc in a magnetic field. The radius of curvature of rc can be measured and then the m/q ratio can be d. Part A After being accelerated to a speed of 1.00×105 m/s, the particle enters a uniform magnetic field of strength 0.900 T and travels in a circle of radius 33.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. ► View Available Hint(s) 17 ΑΣΦ m/q= Submit Previous Answers ? kg/C

Thomson is best known for his discoveries about the re of cathode rays. His other important contribution the invention, together with one of his students, of nass spectrometer, a device that measures the ratio ass m to (positive) charge q of an ion. spectrometer consists of two regions as shown in gure.(Figure 1) In the first region an electric field lerates the ion and in the second the ion follows a lar arc in a magnetic field. The radius of curvature of rc can be measured and then the m/q ratio can be d. Part A After being accelerated to a speed of 1.00×105 m/s, the particle enters a uniform magnetic field of strength 0.900 T and travels in a circle of radius 33.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. ► View Available Hint(s) 17 ΑΣΦ m/q= Submit Previous Answers ? kg/C

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter8: Electromagnetism And Em Waves

Section: Chapter Questions

Problem 7Q

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J. J. Thomson is best known for his discoveries about the nature of cathode rays. His other important contribution was the invention, together with one of his students, of the mass spectrometer, a device that measures the ratio of mass m to (positive) charge q of an ion. The spectrometer consists of two regions as shown in the figure. (Figure 1) In the first region an electric field accelerates the ion and in the second the ion follows a circular arc in a magnetic field. The radius of curvature of the arc can be measured and then the m/q ratio can be Figure V B • Part A Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb. View Available Hint(s) After being accelerated to a speed of 1.21x105 m/s, the particle enters a uniform magnetic field of strength 0.700 T and travels in a circle of radius 35.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. m/q= Submit…
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