This question considers a hypothesis test with H0: μ = 200 and H1: μ ≠200 and significance level 5%. A random sample of 25 taken from a population has mean value 224 and standard deviation 50. Should the null hypothesis be rejected?
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This question considers a hypothesis test with H0: μ = 200 and H1: μ ≠200 and significance level 5%.
A random sample of 25 taken from a population has
Should the null hypothesis be rejected?
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- An economist collects a simple random sample of 32 teacher's salaries in Cititon, and finds a mean of $67,000 and a standard deviation of $8,000. Is there enough evidence to conclude, at a significance of alpha= 0.05, that the mean salary of teachers in Cititon is different than $70,000? What is the test statistic? What is the null hypothesis? What conclusion do we draw? Do we reject the null hypothesis? What is/ are the critical value(s)? What is the alternative hypothesis? What is the p-value for the problem above?Given two independent random samples with the following results: n₁ = 651 x₁ = 307 n2 = 569 x2 = 234 Can it be concluded that there is a difference between the two population proportions? Use a significance level of a = 0.02 for the test. Copy Data Step 5 of 6: Determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion of your answer to two decimal places.You are a researcher verifying the claim that the average adult consumes 1.7 cups of coffee per day. The population standard deviation is 0.5 cups per day. You sample 30 adults and find the average is 1.85 cups per day. Test the claim above at the alpha = 0.05 significance level. What do you conclude about the number of cups of coffee that adults consume each day? Group of answer choices - You cannot reject the null hypothesis. Even though your sample indicated 1.85 cups, there still is not sufficient evidence to overturn the claim that adults consume 1.7 cups per day. - This is a borderline case where the test statistic and the critical values are the same. We can neither accept nor reject the null hypothesis in this case. - You reject the null hypothesis. With thirty people consuming 1.85 cups on average , there is sufficient evidence to overturn the claim that adults consume 1.7 cups per day.
- A quiz related to digital knowledge was conducted. The quiz had 10 questions and covered topics such as the purpose of browser cookies, phishing scams, and privacy policies. The survey was given to 50 people. The mean score is 4.1 with a standard deviation of 2.6. We want to know if the data provide evidence that the mean score in the population is lower than 5. We will use alpha = 0.05 to make our decision. What is the null hypothesis for this question? Group of answer choices a. The proportion of people who pass the test is 5. b. The mean test score of the population is 5. c. The mean test score of the 50 people who took the test is 5. d.The standard deviation is 2.6The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:A sample mean is 137, sample size is 20, and population standard deviation is 14.2 are given. Ho: μ-132, H1: µ#132 and a significance level is 0.05. Use the P-value approach to test the hypothesis. O a. a. z = 2.57; P-value = 0.0101; reject null hypothesis b. z = 0.35; P-value = 0.7263; do not reject null hypothesis O c. z = 1.57; P-value = 0.0582; do not reject null hypothesis O d. z = 1.57; P-value = 0.1164; do not reject null hypothesis
- Suppose the national average dollar amount for an automobile insurance claim is $670.543. You work for an agency in Michigan and you are interested in whether or not the state average is different from the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 670.543, Alternative Hypothesis: μ ≠ 670.543. A random sample of 27 claims shows an average amount of $668.645 with a standard deviation of $68.6867. What is the test statistic and p-value for this test? Question 8 options: 1) Test Statistic: -0.144, P-Value: 0.44345 2) Test Statistic: -0.144, P-Value: 0.5566 3) Test Statistic: -0.144, P-Value: 1.5566 4) Test Statistic: 0.144, P-Value: 0.8869 5) Test Statistic: -0.144, P-Value: 0.8869In a random sample of size 36 we observe a sample mean of 25 and a variance of 144. If we test the hypotheses below with a significance level of 0.05. Ho: µ = 20 HẠ :4 > 20 what will be the calculated test statistic?We want to conduct a hypothesis test of the claim that for middle-aged adults the population's mean of their cholesterol levels is more than 199.3 mgdL. We choose a random sample of such levels. The sample has a mean of 197.3 mgdL and a standard deviation of 19.5 mgdL. For each of the following sampling scenarios, choose an appropriate test statistic for our hypothesis test on the population mean. Then calculate that statistic. Round your answers to two decimal places. (a) The sample has size 105, and it is from a non-normally distributed population with a known standard deviation of 19.2. z = t = It is unclear which test statistic to use. (b) The sample has size 12, and it is from a normally distributed population with an unknown standard deviation. z = t = It is unclear which test statistic to use.