This is a MATLAB Coding problem: Implement a recursive function, called count, that takes two inputs, an array of integers and target integer.  count should search the array for the target integer and return the number of occurrences of the target integer in the array.  For example: disp(count([1, 2, 4, 1, 2, 1], 1)) % Generates 3 disp(count([1, 2, 4, 1, 2, 1], 2)) % Generates 2 disp(count([1, 2, 4, 1, 2, 1], 4)) % Generates 1 disp(count([1, 2, 4, 1, 2, 1], 9000)) % Generates 0

Using recursion, write a Python function def before(k,A) which takes an integer k and an array A of integers as inputs and returns a new array consisting of all the integers in A which come before the last  occurrence of k in A, in the same order they are in A. For example, if A is [1,2,3,6,7,2,3,4] then before(3,A) will return [1,2,3,6,7,2]. If k does not occur in A, the function should return None.

Write a C++ program using classes and recursion functions to covert a number in a given base (the user enters the base - from 2 to 9) to a decimal number. The algorithm states that each successive digit in the number is multiplied by the base raised to the power corresponding to its position in the number. The low-order digit is in position 0. We sum together all of these products to get the decimal value. For example, in binary- base 2, if we have the binary number 111001, we convert it to decimal as follows: 1x25 + 1x2* + 1x2³ + 0x2²+ 0x2² + 1x2º = 57 For a base 5 number, 14230: 1x5 + 4x53 + 2x52 + 3x5+ Ox5° = 1190 Validate your input. You should check for invalid digits and provide an informative error message to the user. This program requires you to use a recursive function for the conversion to decimal. Failure to do that will result in no points awarded.

write a Java program that works like this) passes an array to a function and performs a given operation (any operation) within that function. Loops (the array using iterative loops. Together) if statements

//write a recursion function that will find the largest interger in the string. Can you give me some feedback on this function  public int findMax(String s,intmax) { if (s.length()== 0) return 1; for (int = 0 ; i > s.length() ;i++) if (s.charAt (i) > s.charAt(i) ))   returnmax; returnmax;

Design and implement an algorithm using recursion and backtracking to sort an array of integers into ascending order. Consider the given array as input and produce a sorted array as output. Each time you take an integer from the input array, place it at the end of the output array. If the result is unsorted, backtrack.

in C programing  Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b,4) should return 0.int isSorted(int *array, int n){

Implement a recursive is_palindrome(s:str)->bool function, which checks if the given string is a palindrome or not.       Examples: >>> is_palindrome('racecar') True >>> is_palindrome('racecars') False   please help my homework and put here screenshot.  # instruction said not using loops

Finish the splitOdd10 using recursion to determine if the elements of an array can be split into two groups such that the sum of one group is a non-zero multiple of 10 and the sum of the other group is odd

Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below.   def count_ordered ( seq ) :         """        Input : A sequence of comparable elements        Output : The number of elements that are less than the following element in the sequence        Example :        >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] )        5        >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) )        2        >>> count_ordered ( 'Python' )        2        >>> count_ordered ( [ 6 ] )        0        >>> count_ordered ( [ ] )        0         """          In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…