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- need helpApplying Hardy-Weinberg equilibrium. In a population of 100 individuals, 49% are YY. What percentage is expected to be XY?Heritability is valid for (select all that apply)? a-No answer text provided. b-No answer text provided. c-Multiple populations of a species d-Single populations of a species e-Any environment f-Any point in time g-A specific point in time
- PLEASE ANSWER THE QUESTION AND GIVE THE WHOLE SOLUTION FOR ITCan you please make a conclusion for this? Thank you so much! Suppose you counted 79 R_ and 33 rr. The total number of individuals you counted, N, is 112. You expect 3/4 to be R_ (84) and 1/4 to be rr (28). Are your results close enough to these ratios for you to accept the null hypothesis—that there is no real difference? Individual'sPhenotype Observed number Observed Ratio Expected Ratio Expected Number (Observed no. – Expected no.)^2 / Expected number R_ 79 2.8 3 84 (79-84) ^2 = 25/84 = 0.297 rr 33 1.18 1 28 (33-28) ^2 = 25/28 = 0.893 TOTAL: 112 Chi Square Value = 1.19 Degrees of freedom = 1Keeping Mendel's experiment in mind. Define law of probability and provide an example.
