These are for isomers of two ester compounds of a formula of C4H6O2. The exact wavenumber (cm-1) and %T. Why are the C=O stretching frequencies different for these two esters (Why is one lower in wavenumbers)?

Give detailed Solution with explanation needed...don't give Handwritten answer. don't copy answer anywhere. Don't use Ai for answering this

For each chemical formula, determine the number of molecular ion peaks and the molecular ion height ratio.

Interpet and analyze this Infrared (IR) spectra to show the signs from the peaks and what they tell about the unknown compound.

12 of 15 The range of IR absorption of C=O stretching vibrations (including ketones, aldehydes, carboxylic acids, esters, acyl halides, anhydrides and amides) is: 2260-2240 cm1 -1 1740-1690 cm" 1650-1550 cm1 1850-1550 cm1

What structure is consistent with these spectra? PPM 100 Кey Peaks m/z = 27, 43, 107, 50 109, 150, 152 50 100 150 m/z al Br-

interpret/identify the spectroscopy peaks and its charecteristics (ex. C=O, 4H)

Prepare a table for the infrared spectroscopy results of key diagnostic peaks for both products and the starting alcohol. Products are 2-chloro-2-methylbuntane and 2-bromo-2-methylbutane. Alcohol is 2-methyl-2-buntanol. One column should include the wavenumber frequency and the other column should include the structure/vibration assignment (C(sp3)-H stretching, C-Br stretch, O-H stretch, etc.). Include any C-H stretching and bending frequencies, and likely C-Cl or C-Br frequencies.