THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the AH° (in kJ) for the hypothetical reaction: (Round off final answer to ONE decimal place) 2X2D (g) + 3M2 (g) → 2X2M (I) + 2DM2 (g) AH°f for X2D (g) = -27.5 kJ/mol AH°f for DM2 (g) = -293.9 kJ/mol AH°f for X2M (1) = -284.8 kJ/mol AH°f for M2 (g) = 0 kJ/mol

THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the AH° (in kJ) for the hypothetical reaction: (Round off final answer to ONE decimal place) 2X2D (g) + 3M2 (g) → 2X2M (I) + 2DM2 (g) AH°f for X2D (g) = -27.5 kJ/mol AH°f for DM2 (g) = -293.9 kJ/mol AH°f for X2M (1) = -284.8 kJ/mol AH°f for M2 (g) = 0 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3. Calculate the enthalpy change for the reaction P406 (s) + 2 02 (g) → P4010 (s) given the following enthalpies of reaction: AH = -1640.1 kJ P4 (s) + 3 02 (g) P4 (s) + 5 02 (g) → P406 (s) → P4010 (s) AH = -2940.1 kJ
THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the AH° (in kJ) for the hypothetical reaction: (Round off final answer to ONE decimal place) 2X,D (g) + 3M2 (g) → 2X2M (I) + 2DM2 (g) AH°, for X2D (g) = -25 kJ/mol AH°; for DM2 (g) = -294.1 kJ/mol AH°, for X2M (I) = -280.1 kJ/mol AH°f for M2 (g) = 0 kJ/mol Round your answer to 1 decimal place.
Use Hess's Law to calculate the enthalpy for this reaction: 4SO3(g) → 4S(s) + 602(g) AH° ??? kJ !! rxn Given the following thermochemical equations: SO2(g)→ S(s) + O2{g) AH° = +296.8 kJ 2SO2(g) + O2(g) → 2SO3(g) AH° = -197.8 kJ
In the recovery of iron from iron ore, the reduction of the ore is actually accomplished by reactions involving carbon monoxide. Use the following thermochemical equations, Fe,O3(s) + 3CO(g) 2Fe(s) + 3CO,(g) AH° = - 28 kJ 3Fc,O3() + CO(g) 2Fe3O4() + CO,(g) AH = -59 kJ FezO4(s) + CO(g) 3FcO(s) + CO,(g) AH° = +38 kJ to calculate AH° for the reaction FeO() + CO(g) Fe(s) + CO2(g) AH° = i kJ
Given: 4AICI3(s) + 302(g) → 2Al,O3(s) + 6C12(g); AH=-529.0 kJ determine AH for the following thermochemical equation. Cl,(3) + Al,O;(s) → AICI,(9) + 02(g) O +88.2 kJ O +264.5 kJ O +176.3 kJ O -176.3 kJ O +529.0 kJ
THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the AH° (in kJ) for the hypothetical reaction: (Round off the final answer to ONE decimal place. Do not include the unit.) 2X2D (g) + 3M2 (g) – 2X2M (I) + 2DM2 (g) AH°F for X2D (g) = -24.4 kJ/mol AH°f for DM2 (g) = -290.7 kJ/mol AH°; for X2M (I) = -283.1 kJ/mol AH°; for M2 (g) = 0 kJ/mol
THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the AH° (in kJ) for the hypothetical reaction: (Round off the final answer to ONE decimal place. Do not include the unit.) 2X2D (g) + 3M2 (g) – 2X2M (I) + 2DM2 (g) AH°f for X2D (g) = -26 kJ/mol AH°f for DM2 (g) = -296.8 kJ/mol AH°f for X2M (1) = -286.5 kJ/mol AH°f for M2 (g) = 0 kJ/mol
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Using enthalpies of formation, calculate the standard change in enthalpy for the thermite reaction: 2Al(s) + Fe203(s) → Al203(s) + 2Fe(s) This reaction occurs when a mixture of powdered aluminum and iron(III) oxide is ignited with a magnesium fuse. The following enthalpies of formation are known: AH°; for Fe203(s) = -826 kJ AH°; for Al203(s) = -1676 kJ O 1251 kJ O 2502 kJ O-1251 kJ O 425 kJ 850 kJ O- 2502 kJ -850 kJ -425 kJ
Using the data provided below, calculate the standard enthalpy change for the following reaction: 2LIOH(s) + CO,(g) → Li,CO;(s) + H,O(g) AH,º LIOH(s) = -487.23 %3D kJ/mol AHº CO2(g) = -393.51 kJ/mol AH,º Li¿CO3(s) = -1216.04 kJ/mol AHº H2O(g) = -241.82 kJ/mol %3D - 35.4 kJ O - 89.9 kJ O- 132 kJ
THERMODYNAMICS: Use the given standard enthalpies of formation to calculate the ΔHo (in kJ) for the hypothetical reaction: (Round off the final answer to ONE decimal place. Do not include the unit.) 2X2D (g) + 3M2 (g) → 2X2M (l) + 2DM2 (g) ΔHof for X2D (g) = -22.4 kJ/mol ΔHof for DM2 (g) = -290.7 kJ/mol ΔHof for X2M (l) = -288.3 kJ/mol ΔHof for M2 (g) = 0 kJ/mol show sol'n please.
Given the standard enthalpy changes for the following two reactions: (1) N2(g) + 202(g)N204(g) AH° = 9.2 kJ (2) 2N20(g)2N2(g) + O2(g) AH° = -164.2 kJ what is the standard enthalpy change for the reaction: (3) 2N½0(g) + 302(g)- →2N2O4(g) AH° = ? kJ