There are 4 waves of wavelengths:λ1 = 10m, λ2== 620 × 10⁹m, 12 = 450 × 10¯⁹m, λ4 = 30 x 10-10m.The subscripts in the answer part follow the same rule as it was given for the wavelengths: 1refers to the 1st wave, 2nd refers to the 2nd waves, 3rd refers to the 3rd wave, 4 refers to the 4thwave.Select all that apply:the 4th wave is an UV radiation.The 2nd frequency corresponds to the radio wave range.All the wavelengths correspond to the electromagnetic spectrumonly one wavelength is part of the visible spectrumThe radiation with the highest energy is the 1st wave.The radiation with the highest energy is the 4th wave.The relation between their frequencies is f₁ f2 > f3 < f4The speeds of the waved depends on their wavelength.The 1st frequency corresponds to the radio wave range.

The ticked options are correct.Explanation:Step 1: Consider this image of an electromagnetic…

Answered: There are 4 waves of wavelengths: λ1 =…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A speaker suspended high in the air, away from other objects, emits one spherical wave with total energy 5 J. Assume the waves travel at the speed of sound in air: 343 m/s. Draw the wave 2 seconds and 5 seconds after it was emitted. Label the total energy at each of these times. Label the energy per unit area for each of these times. I would like to know how should I approach this problem when it comes to sound waves and how do I apply total energy in this problem?
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Wave Formula: Example:If a ray of red light has a wavelength of 660nm with a velocity of 3x108 . What is its frequency in air? Solution:f = v/λf = 3x^10^8 / 660 x 10^-9f = 4.55 x 10^14 Hz Kindly compute the following case exercises: a. A ray of yellow light has a wavelength of 560nm with a velocity of 3x108. What is itsfrequency in air? b. A ray of light has a frequency of 5.10 x 1014Hz. What is its wavelength in polycarbonate,where the ray travels at 1.89 x 108 meters? (round off your answer to 3 digits)
What are the parts of this traveling wave? y(x,t) = (9.00 m) sin( (6ñ m¯¹)x + (4ñ rad/s)t - n/8) 5. Wavelength 6. Angular frequency
Rick uses a cutting laser in his engraving business. The frequency associated with the laser light is 2.4 x 10^14 Hz. a) What is the wavelength of the cutting laser light? b) Is this light inside or outside the range of visible light? Recall v = f x (lambda) , where v is wave speed (m/s), f is frequency (Hz) and (lambda) is wavelength (m).
If two light rays one has wavelength A = 680 nm and the other one has wavelength опе 2=530 nm. 6. a) Which light rays travels a smaller distance in 1 second? Explain. b) Which light rays has the smaller frequency? Explain.
AM radio signals are broadcast at frequencies between 550 kHz (kilohertz) and 1600 kHz and travel at 3 x 10^8 m/s. a) What is the range of wavelengths for those signals? b) FM frequencies range between 88 MHz (megahertz) and 108 MHz and travel at the the same speed. What is the range of the FM frequencies.
Answer the following. Show solution.1. The intensity i of light from a bulb is inversely proportional to the square of the distances from the bulb. If I = 90 W/m2 (Watts per square meter) when the distance s = 20 m, find the intensity at a distance s= 10 m.2. The intensity of light from a source is inversely proportional to its square of the distance from the source. If a pocketbook is 2.4 m from the lamp, the illumination on the page of the book is 500 lm/m2 (lumens per square meter). How far must the lamp be moved so that the intensity of light will be doubled?
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Is the formula to be used is v=s/t? If so the answer is 2.07 m/s. However, my teacher told me to use the wavespeed formula that lamda= 2583 cm and frequency is 0.04 Hz. However I think that is wrong. I asked her why lamda is 2583 if it clearly states that the 2583 is the length of the pool not the wave itself. She told me that wavelength and distance is the same. But still I rejected. Is wavelength and distance the same? If not how are they different

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