In a CRT electrons are accelerated from rest by a potential difference of 1.40x10³V These electrons enter a magnetic field with a strength of 2.20x102 T Assuming the electrons are traveling perpendicular to the field what id the radius of the arc of the deflected electrons?

(a) At what speed will a proton move in a circular path of the same radius as the electron in the previous exercise? (b) What would the radius of the path be if tlie proton had the same speed as the election? (c) What would the radius be if the proton had tlie same kinetic energy' as die electron? (d) The same momentum?

An electron of kinetic energy 2000 eV passes between parallel plates that are 1.0 an apart and kept at a potential difference of 300 V. What is the strength of the uniform magnetic field B that will allow the electron to travel undeflected through the plates? Assume E and B are perpendicular.

A proton (m=1.67 x 10-27 kg) travels a distance of 3.2 cm parallel to a uniform electric field 2.9 x 105 V/m between the plates shown in the figure. If the initial velocity is 4.3 x 105 m/s, find the magnitude of its final velocity in m/s (ignore gravity)  Round your answe to 0 decimal places.

If electrons have kinetic energy of 2000 eV, find (a) their speed, (b) the time needed to traverse a distance of 5 cm between plates that our horizontal, and (c) the vertical component of their velocity after passing between the plates if the electric field is 3.33 x 10^3 V/m.

A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (Take, charge of electron = 1.6 × 10-¹9 C)

An electron with a kinetic energy of 1 keV is fired normal to the lines of a field of magnitude 70 G. Find: a) the radius of its path: 28.7*10^-9 m b) its acceleration: 4.35*10^10 m/s2 c) its period: 5.1*10^-9 S

An electron encounters an E and B fields.B field is given by B = 0.1 j T.Electron experiences a force F = (9.6 x 10^-14 i – 9.6 x 10^-14 k)Find the electric field encountered by the electron. The velocity of the electron isv = 5 x 10^6 i m/s.

a) An electron gun is used to produce a beam of electrons with a known velocity. The accelerating voltage is 5000 V and the electron mass and charge are 9.1 x 10-31 kg and -1.6 x 10-19 C respectively. Calculate the velocity of the electrons. b) Electrons in a narrow beam travelling at a steady speed of 4.19 x 107 m/s are directed into the space between two oppositely charged parallel plates which are 419 mm long and 60 mm apart. The plate at the top carries a negative charge and the plate at the bottom carries an equal positive charge. The potential difference between the plates is 250 V. The initial direction of the beam is parallel to the plates and midway between them. Draw a diagram showing the direction of the field lines between the plates. Include a description and sketch the path of the electrons as they travel through the field. i) Calculate the force on each electron between the plates. ii) Calculate the time each electron spends between the plates. Derive a formula relating…

A 5.0 MeV (kinetic energy) proton enters a 0.20 T field, in a plane perpendicular to the field.  What is the radius of its path?