The vibrational levels of 23Na127I lie at the wavenumbers 142.81, 427.31, 710.31, and 991.81 cm−1. Show that they fit the expression (v + 1/2) ᷉v − (v + 1/2) 2xe ᷉v, and deduce the force constant, zero-point energy, and dissociation energy of the molecule.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter27: Molecular Fluorescence Spectroscopy
Section: Chapter Questions
Problem 27.6QAP
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The vibrational levels of 23Na127I lie at the wavenumbers 142.81, 427.31, 710.31, and 991.81 cm−1. Show that they fit the expression (v + 1/2) ᷉v − (v + 1/2) 2xe ᷉v, and deduce the force constant, zero-point energy, and dissociation energy of the molecule.

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