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The value of S is computed from the formula: S= 1/1 + 1/2 + 1/3 + 1/4 + 1/5 + .. + 1/N Write a Java program that can output the number of terms required and the value of S before S exceeds 3.1. Refer to the attached sample runs as your basis. Depicted below is the sample output when the program is executed (the items in red bold characters are inputted by the user, while the items in blue bold characters are calculated and outputted by the program): 1, 1.0000 2, 1.5000 3, 1.8333 ện - 4, 2.0833 5, 2.2833 6, 2.4500 7, 2.5929 8, 2.7179 9, 2.8290 @n - 10, 2.9290 ện - 11, 3.0199 ện - 12, 3.1032 en ện Therefore, the number of terms before s exceeds 3.1 is 11

The value of S is computed from the formula: S= 1/1 + 1/2 + 1/3 + 1/4 + 1/5 + .. + 1/N Write a Java program that can output the number of terms required and the value of S before S exceeds 3.1. Refer to the attached sample runs as your basis. Depicted below is the sample output when the program is executed (the items in red bold characters are inputted by the user, while the items in blue bold characters are calculated and outputted by the program): 1, 1.0000 2, 1.5000 3, 1.8333 ện - 4, 2.0833 5, 2.2833 6, 2.4500 7, 2.5929 8, 2.7179 9, 2.8290 @n - 10, 2.9290 ện - 11, 3.0199 ện - 12, 3.1032 en ện Therefore, the number of terms before s exceeds 3.1 is 11

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The value of S is computed from the formula: S= 1/1 + 1/2 + 1/3 + 1/4 + 1/5 + . + 1/N Write a Java program that can output the number of terms required and the value of S before S exceeds 3.1. Refer to the attached sample runs as your basis. Depicted below is the sample output when the program is executed (the items in red bold characters are inputted by the user, while the items in blue bold characters are calculated and outputted by the program): @n @n @n @n @n @n @n @n @n @n @n 1, 1.0000 2, 1.5000 3, 1.8333 4, 2.0833 5, 2.2833 6, 2.4500 7, 2.5929 8, 2.7179 9, 2.8290 10, 2.9290 11, 3.0199 %3D %3! @n Therefore, the number of terms before s exceeds 3.1 is 11 12, 3.1032 I||| II IIII
Transcribed Image Text:The value of S is computed from the formula: S= 1/1 + 1/2 + 1/3 + 1/4 + 1/5 + . + 1/N Write a Java program that can output the number of terms required and the value of S before S exceeds 3.1. Refer to the attached sample runs as your basis. Depicted below is the sample output when the program is executed (the items in red bold characters are inputted by the user, while the items in blue bold characters are calculated and outputted by the program): @n @n @n @n @n @n @n @n @n @n @n 1, 1.0000 2, 1.5000 3, 1.8333 4, 2.0833 5, 2.2833 6, 2.4500 7, 2.5929 8, 2.7179 9, 2.8290 10, 2.9290 11, 3.0199 %3D %3! @n Therefore, the number of terms before s exceeds 3.1 is 11 12, 3.1032 I||| II IIII
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