The state transition diagram for the logic circuit shown is D CLK Q 10 2-1 MUX X1 XO Y Select Alo
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- (c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).(b) Figure Q2(b) shows input waveforms of A, B and C. Draw the logic circuit that will generate the output waveform X. A Inputs B Output X Figure Q2(b) : Input and output waveformsb) The diode is to be used in the AND logic circuit shown in figure Q1b : VDD R VA VB 0 0 0 1 1 0 1 1l Case 1 Vo Case 3 VA KH V. Case 2 Figure Q1b : Diode - Resistor AND Gate The inputs are assumed to be at rail values where a logic High, '1', is Voo = 5V, and a logic Low, 'O', is OV. Referring to the above truth table : i) What will the output voltage V, in case 1 ? ii) Evaluate the value of the resistor R required to make the threshold voltage for Vo be 1V when operating in case 2. ii) Using this value of R evaluate Vo for case 3. See the Q1 solutions page at the end of the paper
- H.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem LateefAnalyze the logic function of the circuit A₁ B₁ CH D -S₁Implement the circuit (draw the schematic) using the different implementation methods for the 4 logic functions b3M2, b2M2, b1M2 et b0M2: b2M2: With a 16 to 1 multiplexer b1M2: With an 8 to 1 multiplexer. bOM2: With a decoder and an OR logic gate. OOOO 0 D D OD 0 D 1 1 1 1 1 1 1 1 OOOOHHH D 1 1 1 0 D D 0 1 1 1 1 OOHHOHHOCHHOOHH 0 0 1 0 1 1 0 1 CHOHO 0 0 1 D 1 0 CHOHOHOHO. 1 0 1 1 1 0 1 b3 M2 0 ONOC 1 0 0 OOOHPCHAT 0 0 0 1 d 0 1 d d 1 1 d 62 M2 0 HOHOC al 0 0 0 FREETROOT d 1 d d 0 0 d b1 M2 0 HOL 0 0 1 0 1 d 1 0 PPO d d HOD 0 d b0 M2 0 1 0 1 1 0 1 0 d 0 0 d d 0 1 d
- Write an assembly 8051 code to count a hexadecimal digit every second and display it on the 7-segment.Design a logic circuit for decoder that accepts 3-bit input and displays alphabet “048” at the seven- segment as illustrated at Figure 1 (a). The input-output mapping shown in Table 1 (a). Refer Figure 1(b) and Figure 1(c) for seven-segment display format showing arrangements of segments using common anode connection. Show each steps clearly to produce the expressions and required design. [Rekabentuk litar logik untuk penyahkod yang menerima input 3-bit dan paparkan abjad "048" di tujuh-segmen seperti digambarkan pada Rajah 1(a). Pemetaan masukan-keluaran ditunjukkan dalam Jadual 1(a). Rujuk Rajah 1(b) and Rajah 1(c) untuk format paparan tujuh-segmen yang menunjukkan susunan segmen menngunakan sambungan 'common anode'. Tunjukkan setiap langkah dengan jelas untuk menghasilkan ungkapan dan reka bentuk yang dikehendaki.] Xs X6 X7 DECODER Figure 1(a) [Rajah 1(a)] a b с d e f g a 80123456789 Figure 1(c) [Rajah 1(c)] g Figure 1 (b) [Rajah 1(b)] b с DPDesign a counter that counts 1-2-3-5-7 Please explain the following:state diagram state table simplification Logic circuit digital design
- 5. Reduce the combinational logic circuit in Figure below to a minimum form: A B D 7The logic function implemented by the multiplexer circuit is (ground implies a logic "0") 4x1 MUX 1。 1₁ 1₂ 13 S₁ S₂ P Q Y -F13. Complete the following table according to the combinational logic circuit shown in figure below. Inputs Output F AB 00 01 10 B Dec iTiT Mux Mux